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notka56 [123]
3 years ago
10

The second of two numbers is 4 less than twice the first. Their sum is 80.Find the numbers

Mathematics
1 answer:
Otrada [13]3 years ago
4 0
The first number is x
the second number is 2x-4
combine both numbers = 80
x+2x-4=80
3x-4=80
3x=84
x=28
one number is 28 and the other is 52.
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Calculate the sum of the first 36 terms of the arithmetic sequence defined in which a36=14 and the common difference is d=1/8
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Answer:

425.25


Step-by-step explanation:

Since we are given 36th term as 14 and we know common difference is \frac{1}{8}, it means that from the first term, we add \frac{1}{8} to each and get 14 on the 36th term. To figure out the first term, thus, we have to subtract \frac{1}{8} 35 times from 14. Let's do it to get first term:

14-35(\frac{1}{8})=\frac{77}{8}=9.625

The sum of arithmetic sequence formula is:

S_{n}=\frac{n}{2}[2a+(n-1)d]

Where,

  • S_{n} is the sum of nth term (we want to figure this out for first 36 terms)
  • a is the first term (we figured this out to be 9.625)
  • n is the term number (36 for our case)
  • d is the common difference (given as \frac{1}{8})

Substituting all the values, we get:

S_{36}=\frac{36}{2}[2(9.625)+(36-1)(\frac{1}{8})]\\S_{36}=18[19.25+4.375]\\S_{36}=18[23.625]\\S_{36}=425.25

First answer choice is right.


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Step-by-step explanation:

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