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3 years ago

Which multiplication problem is modeled on the number line? 2(– 4) 4(2) 2(4) 4(– 2)

Mathematics

2 answers:

Sliva [168]3 years ago

5 0

Answer:

4(-2)

Step-by-step explanation:

yulyashka [42]3 years ago

3 0

Answer:

4(-2)

Step-by-step explanation:

The correct answer is 4(-2) becasue the leeps to each number has 2 spaces between them and they are moving to the left of the number line that means that it is -2, and there are 4 leaps.

Hopefuly this helped you.

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35/40 reducing fractions

laila [671]

Answer: 7/8

What you have to do here is to find the highest number which can be divided by both. Or you have to divide both the numerator and denominator until it can not be divided by any number anymore. You can do this by finding the highest common factor (<u>HCF)</u> of both the number, 35 and 40.

Highest Common Factor: HCF of two or more numbers is the greatest factor that divides the numbers. For example, 2 is the HCF of 4 and 6.

So, the highest number which divides 35 and 40, is 5. Now 35 divided by 5 is 7 and 40 divided by 5 is 8. The final answer is 7/8 and there is no more numbers which can divide both of them by a specific number.

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6 0

2 years ago

2,550 gallons in 30 days

exis [7]

The answer
is 85 gallons
in a day

3 0

3 years ago

BRAINLIEST!!!!!

Ksivusya [100]

Figure A best represents it because if you add 576 and 49 you get 625, which shows the theorem of a^2+b^2=c^2.

3 0

3 years ago

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The Big Telescope Company sells circular mirrors. Their largest mirrors have radii of 5 meters and their smallest mirrors have r

pogonyaev

Answer: 1:5

Step-by-step explanation:

Given: The cost of every mirror is proportional to the cube of the mirror's radius.

i.e. $\dfrac{\text{Cost of smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{(\text{radii of smallest mirror}^3)}{\text{(radii of largest mirror)}^3}$

Their largest mirrors have radii of 5 meters and their smallest mirrors have radii of 1 meter.

Then,

$\dfrac{\text{Cost of smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{1^3}{(5)^3}=\dfrac{1}{125}$

The ratio of the total cost of 25 of the company's smallest mirrors to the cost of one of the company's largest mirrors will be:

$\dfrac{\text{Cost of 25 smallest mirror}}{\text{Cost of largest mirror}}=\dfrac{25\times 1}{125}=\dfrac{1}{5}$

Hence, the ratio of the total cost of 25 of the company's smallest mirrors to the cost of one of the company's largest mirrors = 1:5 .

5 0

2 years ago

I neeed help asap ill make u brillint

Ber [7]

Answer is ¹/₂

I hope this helps you :)

6 0

2 years ago

Read 2 more answers