Ask question

Ask question

All categories

2 years ago

10

PLZ HELP I WILL MAKE YOU BRAINLIEST NO FAKE LINKS

1 answer:

chubhunter [2.5K]2 years ago

3 0

1st question: C

2nd question: A

You might be interested in

A town has a population of 13000 and grows at 4.5% every year. What will be the population after 13 years, to the nearest whole

hodyreva [135]

23,039.
y=13,000(1.045)^t
t=13
You get 1.045 because you add 1+ the percentage in decimal form.

6 0

2 years ago

Read 2 more answers

SOMEONE PLEASE HELP ME I NEED HELP ASAP

tigry1 [53]

y+4=(5- -4)/(0-3) . (x-3) =>

y+4=-3(x-3)

5 0

2 years ago

A superhero asked his nemesis how many cats she has. she answered with a riddle "Three-fourths of my cats plus seven" how many c

liq [111]

Let C be the number of cats of the superhero. With this, the number of cats of nemesis have is 3C/4 + 7. The numbers should be equal such that,
C = 3C/4 + 7
The value of C from the equation is 28. Thus, the number of cats of the nemesis is 28.

6 0

2 years ago

The rate of growth of profit (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati

Alecsey [184]

Answer:

The function is $P(x) = \frac{1}{2} e^{-x^2} +0.016$

Step-by-step explanation:

From the question we are told that

The rate of growth is $P'(x) = xe^{x} - x^2$

The total profit is $P(2) =$ $25,000

The time taken to make the profit is $x = 2 \ years$

From the question

$P'(x) = xe^{-x^2}$ is the rate of growth

Now here x represent the time taken

Now the total profit is mathematically represented as

$P(x) = \int\limits {P'(x)} \, = \int\limits {xe^{-x^2}} \,$

So using substitution method

We have that

$u = - x^2$

$du = 2xdx$

So

$p(x) = \int\limits {\frac{1}{2} e^{-u}} \, du$

$p(x) = {\frac{1}{2} [ e^{-u}} +c ]$

$p(x) = {\frac{1}{2} e^{-x^2}} + \frac{1}{2} c$ recall $u = - x^2$ and let $\frac{1}{2} c = Z$

At x = 2 years

$P(x) =$ $25,000

So

Since the profit rate is in million

$P(x) =$ $25,000 = $\frac{25000}{1000000} =$ $0.025 millon dollars

So

$0.025 = {\frac{1}{2} e^{-2^2}} + Z$

=> $Z = 0.025 - {\frac{1}{2} e^{-2^2}}$

$Z = 0.016$

So the profit function becomes

$P(x) = \frac{1}{2} e^{-x^2} +0.016$

5 0

3 years ago

University Theater sold 465 tickets for a play. Tickets cost $23 per adult and $13 per senior citizen. If total receipts were $7

liq [111]

<u>Answer:</u>

355 senior citizen tickets were sold.

<u>Step-by-step explanation:</u>

Assuming a to the the ticket of adults and s to be the ticket of senior citizens, we can write two equations as:

$a +s=465$ --- (1)

$23a+13s=7145$ --- (2)

From equation 1, $a=465-s$ .

Substitute $a$ in equation 2 to get:

$23 (465-s) + 13s = 7145$

$10695 - 23s +13s =7145$

$-10s = -3550$

$s = 355$

Therefore, there were 355 senior citizen tickets sold.

8 0

2 years ago