Answer:
(1,3,6,1,3,3)
BrO3-(aq) + 3Sn2+(aq) + 6H+(aq) → Br-(aq) + 3Sn4+(aq) + 3H2O(l)
Explanation:
BrO3-(aq) + Sn2+(aq) --> Br-(aq)+Sn4+(aq)
Separating into half equations, we have;
Sn2+ → Sn4+ + 2e- (Oxidation)
BrO3- + 6e- → Br- (Reduction)
Upon balancing the atoms and charges we have;
Sn2+ → Sn4+ + 2e- (Oxidation)
BrO3- + 6e- + 6H+ → Br- + 3H2O (Reduction)
Make sure electron gain is equal to electron lost, we have;
3Sn2+ → 3Sn4+ + 6e- (Oxidation)
BrO3- + 6e- + 6H+ → Br- + 3H2O (Reduction)
Add both half equations together;
BrO3- + 6e- + 6H+ + 3Sn2+ → Br- + 3H2O + 3Sn4+ + 6e-
Upon simplification;
BrO3-(aq) + 3Sn2+(aq) + 6H+(aq) → Br-(aq) + 3Sn4+(aq) + 3H2O(l)
What are the coefficients of the six species in the balanced equation above?
(1,3,6,1,3,3)