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Nana76 [90]
3 years ago
14

A cord is used to vertically lower an initially stationary block of mass m kg at a constant downward acceleration of g/4. the bl

ock has fallen a distance
d. (use any variable or symbol stated above as necessary.) (a) find the work done by the cord's force on the block. wf = 3mgd 4​ incorrect: your answer is incorrect. (b) find the work done by the weight of the block. wg = (c) find the kinetic energy of the block. k = (d) find the speed of the block. v =
Chemistry
1 answer:
Natali5045456 [20]3 years ago
5 0

(a) We know that work is the product of Force and Distance so: (in this case Distance is negative since going down so –d)

work = force * distance

work = M * (g - g/4) * -d

work = -3Mgd/4 <span>

(b) The work by the weight of the block is simply:</span>

work = Mgd <span>

(c) The kinetic energy is simply equivalent to the net work, therefore:</span>

KE = net work

KE = Mgd/4 <span>

(d) The velocity is:</span>

v = √(2*KE/M)

Plugging in the value of KE from c:

v = √(2*Mgd / 4M)

<span>v = √(gd / 2) </span>

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Determine the enthalpy change for the decomposition of calcium carbonate. CaCO₃(s) --&gt; CaO(s) + CO₂(g) given the thermochemic
Hunter-Best [27]

Answer: c. 179 kJ/mol

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

Given:

Ca(OH)_2(s)\rightarrow CaO(s)+H_2O (l)   \Delta H_1= 65.2 kJ/mol     (1)

Ca(OH)_2(s)+CO_2(g)\rightarrow CaCO_3(s)+H_2O(l)    \Delta H_2= -113.8 kJ/mol   (2)

C(s)+O_2(g)\rightarrow CO_2(g)    \Delta H_3= -393.5 kJ/mol   (3)

2Ca(s)+O_2(g)\rightarrow 2CaO(s) \Delta H_4=-1270.2 kJ/mol    (4)

On subtracting eq (1) from eq (2) we have:

Ca(OH)_2(s)\rightarrow CaO(s)+H_2O(l) - Ca(OH)_2(s)+CO_2(g)\rightarrow CaCO_3(s)+H_2O(l)

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

\Delta H=-113.8-(65.2)kJ/mol=-179kJ/mol

Hence the enthalpy change for the raection is 179.0 kJ/mol.

6 0
3 years ago
What happens when a piece of Mg ribbon is burnt? Name the
algol13

Answer:

When a Magnesium Ribbon is burnt, a powdery substance called magnesium oxide is formed.

Explanation:

There has obviously been a chemical change because several chemical properties of the magnesium have been modified:  the color, the texture and the mass.

The increase in mass is due to the fact that oxygen from the air has combined with the magnesium to make magnesium oxide, MgO.

The chemical equation, Mg + O2  MgO shows this reaction but it needs to be balanced to make 2Mg + O2  2MgO.  

Using stoichiometry, we can convert this eqation into an equation with moles:  

2 mol Mg + 1 mol O2  2 mol MgO.  

Next, we convert to grams using atomic masses obtained from the periodic table:

48g Mg + 32g O2  80g MgO

Lastly, we determine the same thing in the proportions we used.  In other words, we used only 0.15g of Mg (not 48g) so everything needs to be divided by 320.  So 80 / 320 = 0.25 g.  If we burn 0.15 g of Mg, we obtain 0.25 g of MgO.

Hope this helps!!!

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3 years ago
Which of the following is not Made up of atoms?<br> A.Dust<br> B.Golf Ball<br> C.Sound<br> D.The Sun
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The correct answer is C - sound.
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4 years ago
PLS HELP ASAP. list 5 chemicals that contribute to ozone layer depletion?​
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Answer:chlorofluorocarbons (CFCs)

halon.

carbon tetrachloride (CCl4)

methyl chloroform (CH3CCl3)

hydrobromofluorocarbons (HBFCs)

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methyl bromide (CH3Br)

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Explanation:

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3 years ago
Question 5
Zina [86]

Answer:

Explanation:

2.2 g/mL is the answer.

4 0
3 years ago
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