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Nana76 [90]
3 years ago
14

A cord is used to vertically lower an initially stationary block of mass m kg at a constant downward acceleration of g/4. the bl

ock has fallen a distance
d. (use any variable or symbol stated above as necessary.) (a) find the work done by the cord's force on the block. wf = 3mgd 4​ incorrect: your answer is incorrect. (b) find the work done by the weight of the block. wg = (c) find the kinetic energy of the block. k = (d) find the speed of the block. v =
Chemistry
1 answer:
Natali5045456 [20]3 years ago
5 0

(a) We know that work is the product of Force and Distance so: (in this case Distance is negative since going down so –d)

work = force * distance

work = M * (g - g/4) * -d

work = -3Mgd/4 <span>

(b) The work by the weight of the block is simply:</span>

work = Mgd <span>

(c) The kinetic energy is simply equivalent to the net work, therefore:</span>

KE = net work

KE = Mgd/4 <span>

(d) The velocity is:</span>

v = √(2*KE/M)

Plugging in the value of KE from c:

v = √(2*Mgd / 4M)

<span>v = √(gd / 2) </span>

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What is the empirical formula of a vanadium (i) oxide given that 20.38 grams of vanadium combines with oxygen to form 23.58 gram
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V₂O is the empirical formula of a vanadium (i) oxide given that 20.38 grams of vanadium combines with oxygen to form 23.58 grams of the oxide.

The simplest whole number ratio of the atoms of the elements in a specific compound is shown by the empirical formula for that compound. When the mass of each component of a compound or its % composition by mass is known, an empirical formula may typically be computed.

% composition is equal to (mass of an element minus mass of the compound) / 100%.

Given

Vanadium weighs 20.38 g.

The oxide's mass is 23.58 g.

% Vanadium composition: (20.38 g/23.58 g) 100%

= 86.43%

Oxygen mass equals 23.58 g minus 20.38 g

= 3.2 g

100% of oxygen's composition is (3.2/g/23.58 g)

= 13.57%

Atomic mass and number are related by composition percentage.

Vanadium's atomic weight is 50.94 g/mol.

Atomic weight of V = 86.43 / 50.94

= 1.6967

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O atom count is 13.57/16.

= 0.8481

Now on calculation the ratio of Vanadium to the oxygen is

1.6967/0.8481 = 2/1

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Thus V₂O is the empirical formula .

Learn more about empirical formula here brainly.com/question/13058832

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