Answer:
The pressure of CO2 = 0.48 atm
Explanation:
Step 1: Data given
Kp = 0.23
Step 2: The balanced equation
2NaHCO3(s) ↔ Na2CO3(s) + CO2(g) + H2O(g)
Step 3: Calculate the pressure of CO2
Kp = (p(CO2))*(p(H2O))
For 1 mol CO2 we have 1 mol H2O
x = p(CO2) = p(H2O)
Kp = 0.23 = x*x
x = √0.23
x = 0.48
pCO2 = x atm = 0.48 atm
The pressure of CO2 = 0.48 atm
Answer: 218.75 kPa
Explanation:
Carbon dioxide is a gas with chemical formula CO2.
Original volume of CO2 (V1) = 3.50 L
Original pressure of CO2 (P1) = 125 kPa
New pressure of CO2 (P1) = ?
New Volume of CO2 (V2) = 2.0 L
Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law
P1V1 = P2V2
3.50L X 125 kPa = P1 x 2.0L
437.5 L•kPa = 2.0L•P1
Divide both sides by 2.0L
437.5 L•kPa/2.0L = 2.0L•P1/2.0L
218.75 kPa = P1
Thus, the new pressure of carbon dioxide would be 218.75 kPa
The larger the paper airplane the more it will weigh, the more it weighs the more lift will be needed to keep it flying. Eventually weight will become greater than lift and the paper airplane will decend to the ground. In adition the larger the paper airplane the larger its wings can be.
[H_{3}O^{+}] = 0.00770 M
The equilibrium equation representing the dissociation of
Given [H_{3}O^{+}] = 0.00770 M
Let the initial concentration of acid be x and change y
So y = = = 0.00770 M
0.00257 x - 0.00001979 = 0.00005929
x = 0.031 M
Therefore, initial concentration of the weak acid is <u>0.031 M</u>
Sodium, calcium, iron and gold are all metals. They all form metallic bonds, in the form of a shared electron cloud. They all have the electrical conductivity and metallic luster which comes with metallic bonds.