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3 years ago

What force is necessary to accelerates a 1250kg car at a rate of 40 m/s

Chemistry

1 answer:

zalisa [80]3 years ago

8 0

Answer:

F = 50000 N

Explanation:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m

Given data:

Mass of car = 1250 Kg

Acceleration = 40 m/s².

Force = ?

Solution:

F = m × a

F = 1250 Kg × 40 m/s²

Kg.m/s² = N

F = 50000 N

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What are the very small particles that make up all matter?

nadezda [96]

All matter is made up of particles called atoms and molecules (as opposed to being continuous or just including particles). On the following page, the idea is stated as one of four concepts in Dalton's theory: “All matter is composed of tiny, indivisible particles called atoms” (p. 158s).

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3 years ago

What feature of a chemical equation is used to balance the equation and make sure it obeys the law of conservation of mass?

taurus [48]

Answer:

b) coefficient

Explanation:

Refer to this example:

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2 is used as a coefficient in this chemical equation.

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3 years ago

Read 2 more answers

Which statement about carbon dioxide (CO2) is correct?

Zanzabum

Answer:

Explanation:

The carbon-oxygen double bond is polar.

However, carbon dioxide is a linear molecule. The two dipoles cancel out each other.

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3 years ago

WILL MARK BRAINLIEST!!!!

Lyrx [107]

Answer:

5.702 mol K₂SO₄

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Compounds
Moles

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 993.6 g K₂SO₄

[Solve] moles K₂SO₄

Step 2: Identify Conversions

[PT] Molar Mass of K: 39.10 g/mol

[PT] Molar Mass of S: 32.07 g/mol

[PT] Molar mass of O: 16.00 g/mol

Molar Mass of K₂SO₄: 2(39.10) + 32.07 + 4(16.00) = 174.27 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 993.6 \ g \ K_2SO_4(\frac{1 \ mol \ K_2SO_4}{174.27 \ g \ K_2SO_4})$
[DA] Divide [Cancel out units]: $\displaystyle 5.7015 \ mol \ K_2SO_4$

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

5.7015 mol K₂SO₄ ≈ 5.702 mol K₂SO₄

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3 years ago

LiOH+HBr---> LiBr +h20 If you start with 10.0 grams of lithium hydroxide, how many grams of lithium bromide will be produced?

kicyunya [14]

LiOH+HBr---> LiBr +h20. Moles of LiOH = 10/24 = 0.41moles. According to stoichiometry, moles of LiOH = moles of LiBr = 0.41moles. Therefore mass of LiBr =moles of LiBr x molecular weight of LiBr = o.41 x 87 = 35.67g. Hope it helps

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3 years ago