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Mrac [35]
3 years ago
6

A rigid container of O2 has a pressure of 2551 mmHg at a temperature of 713 K. What is the pressure at 273 K?

Chemistry
2 answers:
solniwko [45]3 years ago
5 0

Answer:977.34

Explanation:

divide 2551 and 273 to get 3.778. then multiply 3.78 by 273 to gry 977.34.

dangina [55]3 years ago
4 0

Answer:

i do not know

Explanation:

im taking my final exam right now and need the answer, did you ever figure it out

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Geologic time is a way to _______.
mylen [45]

Answer: Geologic time is a way to measure the sequence of events on Earth over time

Explanation:

3 0
3 years ago
What term describes the process of lowering the boiling point of a hydrocarbon by exposing it to different environmental treatme
IgorLugansk [536]

Answer:

Cracking.

Explanation:

A chemical reaction can be defined as a reaction in which two or more atoms of a chemical element react to form a chemical compound. An example of a chemical reaction involving hydrocarbons is cracking.

Hydrocarbon can be defined as an organic compound that comprises of hydrogen and carbon only.

In Organic chemistry, cracking refers to the process of lowering the boiling point of a heavy, complex or long-chain hydrocarbon such as kerogens by exposing it to different environmental treatments such as hydrogen enriched catalysts, pressure or high temperatures, in order to produce smaller, lighter and more useful molecules (alkanes and alkenes) such as gasoline, diesel fuel, etc.

8 0
3 years ago
Why do you Think you weight less on Uranus than earth even though it is more massive planet ? 
Phantasy [73]

Answer:

You would weigh less on Uranus than on Earth because Uranus is far less mass-ive and dense than the Earth. This means that there is less gravity. Therefore, you would weigh less.

Explanation:

Even though Uranus is bigger, it is less massive; that is, there is less mass that makes up the planet. The volume of the planet might be larger, but the actual amount of mass isn't.

By the way, you couldn't stand on Uranus. It's made of gas!

7 0
3 years ago
Calculate the standard emf for the following reaction:
krek1111 [17]
In order to solve this, we need to know the standard cell potentials of the half reaction from the given overall reaction.
The half reactions with their standard cell potentials are:
<span>2ClO−3(aq) + 12H+(aq) + 10e- = Cl2(g) + 6H2O(l) 
</span><span>E = +1.47 
</span>
<span>Br(l) + 2e- = 2Br- 
</span><span>E = +1.065
</span>
We solve for the standard emf by subtracting the standard emf of the oxidation from the reducation, so:
1.47 - 1.065 = 0.405 V
4 0
3 years ago
Some organic solvents do not work well in liquid-liquid aqueous extractions. Ethanol (HOCH2CH3) is a common inexpensive solvent,
erica [24]

Answer:

See explanation

Explanation:

Extraction has to do with the separation of the components of a mixture by dissolving the mixture in a set up involving two phases. One phase is the aqueous phase (beneath) while the other is the organic phase (on top). The solvents used for the two phases must not be miscible. Water commonly is used for the aqueous phase.

Ethanol is an important solvent in chemistry but the solvent is miscible with water in all proportions. As a result of this, ethanol is a poor solvent for carrying out extraction.

4 0
3 years ago
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