Put it in an improper fraction by multiply the coefficient with the denominator and add the numerator.
5/2 , 14/3
Find a common denominator which would be 6.
5/2 = 15/6 , 28/6
Add those together.
15/6 + 28/6 = 43/6
Since it can't be simplified the answer is 43/6
Answer: The Median: 78, The First Quartile: 63, and The Third Quartile: 99
Step-by-step explanation: Ok, so let's put the data set from least to greatest....
(63, 63, 76,) (77, 79,) (84, 99, 99)
First Quartile Third Quartile
First, let's find the median, since you made a little mistake...
77 + 79 = 156
156 ÷ 2 = 78
The median is 78!
Now, let's determine the first quartile and the third quartile.
For the the first quartile/third quartile it'll be the middle number, if it's even we'll do the same extra step just like we'll do for the median. In this case it's not even therefore...
First Quartile: 63
Third Quartile: 99
I hope this helps!
Given:
The two expressions are
To find:
Whether the given expression are equivalent or non-equivalent.
Solution:
If two expressions are looking different but they are equal after simplification, then they are called equivalent expressions.
The first expression is
The first expression is equal to the second expression after the simplification.
Therefore, the given expressions are equivalent.
Let’s assume that Laura has x$
Jose = 8+ x
Keith= 3x
So the total is equal to
118= x + 8 +x + 3x
118= 5x + 8
Subtract 8 from both sides
110= 5x
Divide 5 by both sides
22$= x which is what Laura has
Jose will have :8+22= 30$
Keith will have :3*22=66$
Answer:
g(x) = -|x| + 1
Step-by-step explanation:
Let g(x) be the transformation function
-|x| reflects f(x) across the x-axis. Add 1 to move the result up one unit
So, g(x) = -|x| + 1
