Well i can't really help you in this since i do not know the cost of each calendar, but if you need the formula.
the cost of one calendar = x
so the total cost would be 200 times x (200x)
A:
(f+g)(x)=f(x)+g(x)
(f+g)(x)=4x-5+3x+9
(f+g)(x)=7x+4
B:
(f•g)(x)=f(x)•g(x)
(f•g)(x)=(4x-5)(3x+9)
(f•g)(x)=12x^2-15x+36x-45
(f•g)(x)=12x^2+21x-45
C:
(f○g)(x)=f(g(x))
(f○g)(x)=4(3x+9)-5
(f○g)(x)=12x+36-5
(f○g)(x)=12x+31
Answer: Yes he will be
Step-by-step explanation:
To find out if Ted can afford the car, find the future value of $4,300 in three years.
First convert the number of years and rates to quarterly values as this is the compounding period:
Term = 3 * 4 quarters = 12 quarters
Rate = 5.5% / 4 = 1.375% per quarter
Future value = Amount * ( 1 + rate) ^ term
= 4,300 * ( 1 + 1.375%)¹²
= $5,065.69
<em>Considering that Ted makes $5,065.69 in 3 years, he will be able to buy a car that costs $4,700.</em>
