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Mashutka [201]
3 years ago
8

Can I get help with this? Thanks!

Mathematics
2 answers:
Keith_Richards [23]3 years ago
6 0
X=hamburgers
y=hotdogs

3y+2x=8.00
AND
2y+3x=8.25

Now we've got a system of equations!

Choose a method to solve it, and I think you'll be good from there.

If you need more guidance to the answer, tell me in the comments.

BEST OF LUCK:)


Mnenie [13.5K]3 years ago
5 0
Sorry I can't see what you posted but what do you nerd help with?
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Consider the expression? <br> Please help me !
Arada [10]

Answer:

sqrt(-8x+5)

Step-by-step explanation:

(5-8x)

-----------------

sqrt(-8x+5)

We need to rationalize the denominator

(5-8x)               sqrt(-8x+5)

----------------- * ---------------

sqrt(-8x-5)         sqrt(-8x+5)

(5-8x)               sqrt(-8x+5)

----------------- * ---------------

(-8x+5)

The first term cancels

sqrt(-8x+5)

8 0
3 years ago
Read 2 more answers
I need<br> Help on this one
elixir [45]
The answer is
X=7
Have a nice day <3
5 0
3 years ago
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what is the circumference of a circle if the radius of the circle is 2.2 in terms of pi? a) 1.1 pi b) 1.21 pi c) 2.2 pi d) 4.4 p
Darya [45]
Cicumference =  Dπ  or  2rπ

thus if r = 2.2 
then C  = 2 (2.2)π
             =  4.4π

D is the answer
7 0
3 years ago
What is 3.98 X10 raise to power 10 In standard form
bonufazy [111]
39,800,000,000 is the correct answer, I believe.
3 0
3 years ago
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Chicos estoy en un aprieto ayudarme pls Sabiendo que una falda es 5 € más cara que una blusa y que si compro 6 faldas y 4 blusas
poizon [28]

Answer:

El precio de la falda es 50 €.

Step-by-step explanation:

Lo que sabemos:

F = 5 + B   (1)

En donde F es por falda y B por blusa.

Si compras 6 faldas y 4 blusas y pagas 480 €:

6F + 4B = 480  (2)

Entonces, al introducir la ecuación (1) en (2) podemos hallar el precio de cada falda.

6F + 4B = 480

6(5 + B) + 4B = 480

10B = 480 - 30

B = \frac{450}{10} = 45  

Finalmente, el precio de la falda se puede encontar con la ecuación (1):

F = 5 + 45 = 50

Por lo tanto, el precio de la falda es 50 €.  

Espero que te sea de utilidad!      

7 0
2 years ago
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