Answer:
1. P(P) = 8/20 = 0.4
2. P(G) = 12/20 = 0.6
Step-by-step explanation:
Given;
Number of green marbles G = 12
Number of purple marbles P = 8
Total T = 12+8 = 20
The probability that you choose a purple marble P(P) is;
P(P) = number of purple marbles/total number of marbles
P(P) = P/T = 8/20 = 0.4
P(P) = 0.4
The probability that you choose a Green marble P(G) is;
P(G) = number of Green marbles/total number of marbles
P(G) = G/T = 12/20 = 0.6
P(G) = 0.6
Answer:
we can conclude that there is no significant evidence to conclude that the mean score in 2010 differs from the mean score in 2009.
Step-by-step explanation:
H0 : μ = 582
H1 : μ < 582
Test statistic :
T = (xbar - μ) ÷ σ/√n
Xbar = 515 ; n = 20 ; σ = 120
T = (515 - 582) ÷ 120/√20
T = -67 / 26.832815
T = 2.50
Pvalue at t score = 2.50 ; df = 19 is 0.0187
At α = 0.0187
Pvalue > α ; Hence, we fail to reject the Null
Hence, we can conclude that there is no significant evidence to conclude that the mean score in 2010 differs from the mean score in 2009.
Answer:
9 years old.
Step-by-step explanation:
Since the ages of all of these students are being represented in relation to the middle student's age then we can create formulas for each student and then apply them to the formula for the sum of their ages and solve for the middle child's age (M) like so... (oldest child's age is represented by variable O and youngest child's age is represented by variable Y)
O = M + 6
Y = M - 3
30 = (M+6) + M + (M-3) ... combine like terms
30 = 3M + 3 ... subtract 3 from both sides
27 = 3M ... divide both sides by 3
9 = M
Now we know that the middle child is 9 years old.
