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3 years ago

Which applies the power of a power rule properly to simplify the expression (710)5?

2 answers:

6 0

The power to a power rule is : KEEP THE BASE AND MULTIPLY THE POWERS.
Ex. (x^3)^4 = x^(3*4) = x^12

So ....
(7^10)^5 = 7^50
Last option is correct.

Ne4ueva [31]3 years ago

3 0

Answer:

(7^10)^5= 7^50

Step-by-step explanation:

Givene expression is

(7^10)^5

we apply power of power rule

(a^m)^n = (a)^mn

As per this property we multiply the outside exponent with the exponent inside. multiply the exponent 10 and 5 that gives us 50

$(7^{10}) ^ 5= 7^{10*5} = 7^{50}$

So (7^10)^5= 7^50

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Step-by-step explanation:

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2 years ago

A. Name the smallest angle and the largest angle of the following triangles: F 6 S 5 1. A J 5.03 7 5 G B H 5.1 2. D 4 3 E

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Answer:

(smallest, largest) = (B, C), (D, E), (G, J)

Step-by-step explanation:

Side lengths of a triangle are proportional to the sine of the opposite angle. In a triangle, a larger angle will always have a larger sine. That means the smallest angle is opposite the shortest side, and the largest angle is opposite the longest side.

The shortest side is 5 units, opposite angle B. The longest side is 7 units, opposite angle C.

smallest angle: B
largest angle: C

The shortest side is 3 units, opposite angle D. The longest side is 5 units, opposite angle E.

smallest angle: D
largest angle: E

The shortest side is 5 units, opposite angle G. The longest side is 5.1 units, opposite angle J.

smallest angle: G
largest angle: J

_____

<em>Additional comment</em>

Angles in a triangle may exceed 90°. The sine function actually is decreasing for angles above 90°. However, since the total of angles of a triangle must be exactly 180°, there <em>cannot be two angles in a triangle such that the smaller angle has the larger sine</em>.

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2 years ago

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2 years ago

Read 2 more answers

Which statements about the hyperbola are true? Check all that apply. A. There is a focus at (0,−10). B. There is a focus at (0,

hichkok12 [17]

Answer:

A. There is a focus at (0,−10).

Step-by-step explanation:

Assume the hyperbola is like the one below.

The hyperbola is vertical and centred on the y-axis, so its general equation is

$\dfrac{y^{2}}{a^{2}} - \dfrac{x^{2}}{b^{2}} = 1$

The vertices of your parabola are (0,±8) so a = 8.

The covertices are (±6,0), so b = 6.

Calculate c

$\begin{array}{rcl}a^{2} + b^{2} & = & c^{2}\\8^{2} + 6^{2} & = & c^{2}\\64 + 36 & = & c^{2}\\100 & = & c^{2}\\c & = & \mathbf{10}\\\end{array}$

A. Foci

The foci are at (0, ±c) = (0, ±10)

TRUE. There is a focus at (0,-10).

B. Foci

The foci are at (0,±10).

False. There is no focus at (0,12)

C. and D. Asymptotes

The equations for the asymptotes are

$y = \pm\dfrac{a}{b}x = \pm\dfrac{8}{6}x = \pm\dfrac{4}{3}x$

So, y = ±x are not asymptotes.

False.

E. and F. Directrices

The equations of the directrices are

y = ±a²/c = ±64/10 = ±6.4

y = 6.4 is a directrix.

E is false. x = cannot be a directrix

F is uncertain. Your equation for the directrix is incomplete.

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3 years ago