Answer:
search in anywhere
Step-by-step explanation:
or do it in calculator
or ask from your teacher
ans : A) y= 0.25x + 3
B) y= 0.25x - 4.5
C) y= 4x + 18
D) y= 4x - 42
General equation of a circle with centre (h, k) is given by:
![(x - h)^{2} + (y - k)^{2} = r^{2}](https://tex.z-dn.net/?f=%28x%20-%20h%29%5E%7B2%7D%20%2B%20%28y%20-%20k%29%5E%7B2%7D%20%3D%20r%5E%7B2%7D)
Now, the origin is the centre and radius is 20, so substituting these points in yields:
![x^{2} + y^{2} = 20^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%20y%5E%7B2%7D%20%3D%2020%5E%7B2%7D)
Step-by-step explanation:
rational expression can be written as a ratio and all neutral numbers xan be written as a ratio
root of 26 is irrational because it can't be written as a ratio since its not a whole number.
Hello there!
6.55 ÷ 10 = .655
1 pound would cost about $0.65
Given:
A solution of 60% fertilizer is to be mixed with a solution of 21% fertilizer to form 234 liters of a 43% solution.
To find:
The quantity of the 60% solution in the mixture.
Solution:
Let x be the quantity of the 60% solution and y be the quantity of the 21% solution.
Quantity of mixture is 234. So,
![x+y=234](https://tex.z-dn.net/?f=x%2By%3D234)
...(i)
The mixture has 43% fertilizer. So,
![\dfrac{60}{100}x+\dfrac{21}{100}y=\dfrac{43}{100}\times 234](https://tex.z-dn.net/?f=%5Cdfrac%7B60%7D%7B100%7Dx%2B%5Cdfrac%7B21%7D%7B100%7Dy%3D%5Cdfrac%7B43%7D%7B100%7D%5Ctimes%20234)
Multiply both sides by 100.
...(ii)
Using (i) and (ii), we get
![60(234-y)+21y=10062](https://tex.z-dn.net/?f=60%28234-y%29%2B21y%3D10062)
![14040-60y+21y=10062](https://tex.z-dn.net/?f=14040-60y%2B21y%3D10062)
![-39y=10062-14040](https://tex.z-dn.net/?f=-39y%3D10062-14040)
![-39y=-3978](https://tex.z-dn.net/?f=-39y%3D-3978)
Divide both sides by -39.
![\dfrac{-39y}{-39}=\dfrac{-3978}{-39}](https://tex.z-dn.net/?f=%5Cdfrac%7B-39y%7D%7B-39%7D%3D%5Cdfrac%7B-3978%7D%7B-39%7D)
![y=102](https://tex.z-dn.net/?f=y%3D102)
Putting this value in (i), we get
![x=234-102](https://tex.z-dn.net/?f=x%3D234-102)
![x=132](https://tex.z-dn.net/?f=x%3D132)
Therefore, 132 liters of the 60% solution must be used.