We have been given that a colleague has been tutoring six students in 11th grade to prepare for the ACT. Student scores were as follows: 20, 18, 16, 15, 23, 20. We are asked to find the mean of the ACT scores.
We will use mean formula to solve our given problem.
Upon rounding to nearest whole number, we will get:
Therefore, the mean of the ACT scores is 19 and option 'c' is the correct choice.
Answer:
1. 8% of 50 is 4
2. 95% of 40 is 38
3. 42% of 263 is 110.46
4. 110% of 70 is 77
5. 115% of 20 is 23
6. 130% of 78 is 101.4
7. 6.5% of 50 is 3.25
37. 15% of 50 is 7.5
38. 5% of 19 is 0.95
39. 8% of 275 is 22
I hope this helps! Can I plz have a Brainliest??
Step-by-step explanation:
The answer is true.
Method 1:
The given function is a cubic function. And inverse of a cubic function is also a function.
Method 2:
Since the function is one-to-one function i.e it passes the horizontal line test, its function will pass the vertical line test which is a test if a relation is a function or not.
So, yes the inverse of G(x) will be a function.
Answer:
The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.
Step-by-step explanation:
According to DeMorgan's Theorem:
(W.X + Y.Z)'
(W.X)' . (Y.Z)'
(W'+X') . (Y' + Z')
Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.
For the original function:
(W . X + Y . Z)'
= (1 . 1 + 1 . 0)
= (1 + 0) = 1
For the compliment:
(W' + X') . (Y' + Z')
=(1' + 1') . (1' + 0')
=(0 + 0) . (0 + 1)
=0 . 1 = 0
Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.
Without the parenthesis the compliment equation looks like this:
W' + X' . Y' + Z'
1' + 1' . 1' + 0'
0 + 0 . 0 + 1
Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.
Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.
Answer:
Below.
Step-by-step explanation:
2x+4 = (x²)²÷2
2x + 4 = x^4/2
x^4 = 4x + 8
x^4 - 4x - 8 = 0
We can try trial an error to solve this
Looks like x = 2 fits it:
2^4 - 4(2) - 8
= 16 -8 -8 = 0
so x = 2 is one solution.
I can't find any other solution among other integers.
To find the other solutions you can draw a graph manually or by using software.
There will be either 1 or 3 more real solutions.
I used software to draw the graph and found one other solution:
x = -1.296
