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While a car is running, the alternator provides current to the battery and recharges it. which reaction occurs at the anode of a

Marat540 [252]

While a car is running, the alternator provides current to the battery and recharges it. Reduction reaction occurs at the anode of a lead-storage battery during this process .

The Lead-acid battery or lead-storage battery is one of the oldest types of rechargeable batteries.

Lead-storage batteries can be classified as secondary batteries. The chemical reactions that occur in secondary cells are reversible. The chemical process of extracting current from a secondary battery (forward reaction) is called discharging. The method of regenerating active material is called charging.

While recharging, the automobile battery functions like an electrolytic cell. The energy required to drive the recharging comes from an external source, such as an engine of a car. While charging reduction takes place at anode and while discharging oxidation takes place at anode.

To learn more about Lead storage batteries here

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6 0

2 years ago

Can someone help me with 1-2

ira [324]

Can't really plot a graph here for question 1.

2a) The car speeds up from A to B. The car travels at a constant speed from B to C. The car slows down to a stop from C to D.

b) From the graph, at 10 seconds, the car is moving at 20 m/s.

4 0

4 years ago

A worker pushes a 1080 N crate with a horizontal force of 345 N a distance of 14 m. Assume the coefficient of kinetic frictin be

amm1812

Answer:

The work done by the worker on the crate is 4830 J.

Explanation:

Given that,

Force = 1080 N

Horizontal force = 345 N

Distance d = 14 m

Coefficient of friction = 0.22

We need to calculate the work done

Using formula of work done

$W = Fd$

F = force

d = distance

Put the value into the formula

$W=345\times14$

$W=4830\ J$

Hence, The work done by the worker on the crate is 4830 J.

3 0

3 years ago

Read 2 more answers

An image of a car with height of 14 cm occurred in the mirror which is located at a T-

Thepotemich [5.8K]

Answer:

The distance of car form the mirror is 330 cm.

Explanation:

height of object, h = 140 cm

height of image, h' = 14 cm

radius of curvature, R = 60 cm

focal length, f = R/2 = + 30 cm

Let the distance of image is v and the distance of object is u.

$\frac{h'}{h}\frac{v}{u}\\\\\frac{14}{140} =\frac{v}{u}\\\\v =\frac{u}{10}$

Use the formula of focal length

$\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\\\frac{1}{30}=\frac{10}{u}+\frac{1}{u}\\\\\frac{1}{30}=\frac{11}{u}\\\\u = 330 cm$

3 0

3 years ago

Water has a specific heat capacity nearly nine times that of iron. Suppose a 50-g pellet of iron at a temperature of 200∘C is dr

miv72 [106K]

Answer:

a. closer to 20∘C

Explanation:

$m_{p}$ = mass of pallet = 50 g = 0.050 kg

$c_{p}$ = specific heat of pallet = specific heat of iron

$T_{pi}$ = Initial temperature of pellet = 200 C

$m_{w}$ = mass of water = 50 g = 0.050 kg

$c_{w}$ = specific heat of water

$T_{wi}$ = Initial temperature of water = 20 C

$T_{e}$ = Final equilibrium temperature

Also given that

$c_{w} = 9 c_{p}$

Using conservation of energy

Energy gained by water = Energy lost by pellet

$m_{w} c_{w} (T_{e} - T_{wi}) = m_{p} c_{p} (T_{pi} - T_{e})\\(0.050) (9) c_{p} (T_{e} - 20) = (0.050) c_{p} (200 - T_{e})\\ (9) (T_{e} - 20) = (200 - T_{e})\\T_{e} = 38 C$

hence the correct choice is

a. closer to 20∘C

4 0

4 years ago