All categories

3 years ago

Draw a net force arrow on the picture below. What is the net force? State the direction.

Physics

2 answers:

zalisa [80]3 years ago

6 0

Answer:

Net force=0 N

Explanation:

The drawing will look like the attached image, with no net force on the object. We stablished a reference system located in the center of the body, with + axis take right and upward for x and y. All forces are on the x axis, there is one positive force of 7 N (pointing right) and to negative forces of -4 and -3 N (pointing left) if we add the vectors in the x axis we have that

+7-4-3=0 N

The net force is then 0 newton and the drawing has no net force vector then

exis [7]3 years ago

5 0

Answer: No arrow; no net force.

Explanation: -7 + 7= 0 same thing here

You might be interested in

A small but bright light is at the bottom of a pool 2.2 m deep. How wide is the circle of light that exits the surface of the

mixas84 [53]

Answer: 1.65m

Explanation:

Refractive index in terms of the depth of liquid is the ratio of the real depth to the apparent depth of the liquid i.e Refractive index =Real depth/apparent depth

Refractive index of water given = 1.33

Real depth is the measure of how deep is the liquid while apparent depth is the depth at the surface of the liquid.

Real depth = 2.2m

Apparent depth =?

Applying the formula above

Apparent depth =Real depth/refractive index

= 2.2/1.33

= 1.65m

Therefore, the circle of light that exits the surface of the water when that light shines in the middle of the night is 1.65m wide

5 0

2 years ago

Which of the following examples illustrates static friction?

vivado [14]

Answer:

A box sits stationary on a ramp

Explanation:

Static friction is a force which keeps an object at rest as it is in the case of the box. It has to be overcome for the object to be set into motion.

Static force of friction is calculated as follows:

F= μη

F is static force of friction.

μ is the coefficient of static friction.

η is the normal force.

6 0

3 years ago

A 1.30-m string of weight 0.0125 N is tied to the ceiling at its upper end, and the lower end supports a weight W. Neglect the v

atroni [7]

Answer:

1. t = 0.0819s

2. W = 0.25N

3. n = 36

4. y(x , t)= Acos[172x + 2730t]

Explanation:

1) The given equation is

$y(x, t) = Acos(kx -wt)$

The relationship between velocity and propagation constant is

$v = \frac{\omega}{k}=\frac{2730rad/sec}{172rad/m}\\\\$

v = 15.87m/s

Time taken, $t = \frac{\lambda}{v}$

$= \frac{1.3}{15.87}\\\\=0.0819 sec$

t = 0.0819s

The velocity of transverse wave is given by

$v = \sqrt{\frac{T}{\mu}}$

$v = \sqrt{\frac{W}{\frac{m}{\lambda}}}$

mass of string is calculated thus

mg = 0.0125N

$m = \frac{0.0125N}{9.8N/s}$

m = 0.00128kg

$\omega = \frac{v^2m}{\lambda}$

$\omega = \frac{(15.87^2)(0.00128)}{1.30}$

$\omega =$ 0.25N

The propagation constant k is

$k=\frac{2\pi}{\lambda}$

hence

$\lambda = \frac{2\pi}{k}\\\\\lambda = \frac{2 \times 3.142}{172}$

$\lambda =$ 0.036 m

No of wavelengths, n is

$n = \frac{L}{\lambda}\\\\n = \frac{1.30m}{0.036m}\\$

n = 36

The equation of wave travelling down the string is

$y(x, t)=Acos[kx -wt]\\\\becomes\\\\y(x , t)= Acos[(172 rad.m)x + (2730 rad.s)t]$

$without, unit\\\\y(x , t)= Acos[172x + 2730t]$

7 0

3 years ago

The amount of oxygen in the reactants is 4 atoms. In the products, the oxygen is distributed to water (H2O) and O2 gas. Which co

svp [43]

Answer:

2 in front of water and 1 in front of oxygen

Explanation:

3 0

2 years ago

Read 2 more answers

Complete the table. can I please get help will give points to whoever

MA_775_DIABLO [31]

Answer: proton mass 1 and neutron has no mass number

Explanation: proton because of positive charge neutron because of negative charge

4 0

1 year ago