Draw a net force arrow on the picture below. What is the net force? State the direction.
2 answers:
Answer:
Net force=0 N
Explanation:
The drawing will look like the attached image, with no net force on the object. We stablished a reference system located in the center of the body, with + axis take right and upward for x and y. All forces are on the x axis, there is one positive force of 7 N (pointing right) and to negative forces of -4 and -3 N (pointing left) if we add the vectors in the x axis we have that
+7-4-3=0 N
The net force is then 0 newton and the drawing has no net force vector then
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Answer:
10250 N/C leftwards
Explanation:
QA = 4 micro Coulomb
QB = - 5 micro Coulomb
AP = 6 m
BP = 2 m
A is origin, B is at 4 m and P is at 6 m .
The electric field due to charge QA at P is EA rightwards
The electric field due to charge QB at P is EB leftwards
The resultant electric field at P due the charges is given by
E = EB - EA
E = 11250 - 1000 = 10250 N/C leftwards
