Given that v=u+at derive an equation of motion devoid t

A truck covers 40.0 m in 7.10 s while uniformly slowing down to a final velocity of 2.05 m/s.

Alona [7]

Answer:

(A) Original speed= 9.22 m/s

(B) Acceleration= -1.0099 m\s^2

Explanation:

A truck covers 40m in 7.10 secs

The truck slows down at a uniform velocity of 2.05 m/s

(A) The original speed can be calculated as follows

Vo= 2(40)/7.10 - 2.05

= 80/7.10 - 2.05

= 11.2676 - 2.05

= 9.22m/s

(B) The acceleration can be calculated as follows

a= Vf-Vo/t

= 2.05-9.22/7.10

= -7.17/7.10

= -1.0099m/s^2

5 0

3 years ago

the car starts from rest at s=0 and increases its speed at at=4m/s^2. Determine the time when the magnitude of acceleration beco

dem82 [27]

Answer:

Time = 5 seconds

Distance = 50 meters

Explanation:

Constantly Accelerated Motion

When the velocity of a moving object changes at a constant rate, called acceleration, the velocity changes in same amounts in the same times. The question has a mistake when asking when the acceleration is 20 m/s. If the acceleration is constant, the only variable that can change to that value is the velocity. The equation to calculate the speed is

$v_f=v_o+a.t$

And the distance s is

$\displaystyle s=v_o.t+\frac{gt^2}{2}$

Given the object starts from rest, vo=0 and vf=20 m/s at $a=4\ m/s^2$ . We compute t

$\displaystyle t=\frac{v_f-v_o}{a}=\frac{20-0}{4}$

$\boxed{t=5\ sec}$

Now we compute s

$\displaystyle s=0+\frac{4\times 5^2}{2}$

$\boxed{s=50\ m}$

5 0

3 years ago

Calculate the total force on the Earth due to Venus, Jupiter, and Saturn, assuming all four planets are in a line. The masses ar

Furkat [3]

You need to consider the following:
Me (mass of Earth) = 5.98 x 10^24 kg
Ms (mass of Sun) = 1.99 x 10^30 kg 
G = 6.67 x 10^-11 N 

Formula:
F = G * M1M2/r^2
The ratio FT/F = 4.02x10^-4 / 14.8
= 2.72x10^-5

Since,
1/2.72x10^-5 = 36800
The fraction ratio is 1/36800
= 9.56x10^17 N

3 0

3 years ago

Read 2 more answers

the velocity of a car traveling in the positive direction decreases from 32 m/s to 24 m/s in 4 seconds. what is the average acce

anastassius [24]

Answer:

$a=-2m/sec^2$

Negative sign shows that velocity of the car is decreases at a constant rate

Explanation:

We have given velocity of the car is decreases from 32 m /sec to 24 m/sec in 4 second

So initial velocity of the car u = 32 m /sec

And finally car reaches to a velocity of 24 m/sec

Time taken to change in velocity = 4 sec

So final velocity v = 24 m/sec

From first equation of motion v = u+at

So $24=32+a\times 4$

$a=-2m/sec^2$

Negative sign shows that velocity of the car is decreases at a constant rate

6 0

3 years ago

List and explain briefly similarities and differences between the electric force between two charges and the gravitational force

bazaltina [42]

Answer:

Please see below as the answers are self-explanatory.

Explanation:

Similarities

1) The resultant force is along the line that joins both charges or both masses (assuming both objects can be represented as points)

2) Both type of forces obey Newton's 3rd law.

3) Both are proportional to the product of the property that is affected by the force (charges and masses)

4) Both obey an inverse - square law (consequence of our universe being three-dimensional)

Differences

1) Main difference, is that while the gravitational force is always attractive, the electrostatic force can be attractive or repulsive, as there are two types of charges, which attract each other being of different type, and repel each other if they are of the same type.

2) It is possible, artificially, to block the influence of the electrostatic force, shielding a room, for instance, which is not possible for the gravitational force.

6 0

3 years ago

Given that v=u+at derive an equation of motion devoid t​

Given that v=u+at derive an equation of motion devoid t