I am positive with my and answer and i think yes
Answer:
The velocity of ball and man after catching ball is ![2m/s](https://tex.z-dn.net/?f=2m%2Fs)
Explanation:
Since there is no friction and no external force the momentum is conserved .
Here when man catches ball then man and ball move with common velocity .
Let the final common velocity be
,
Given that mass of the ball is
=![15kg](https://tex.z-dn.net/?f=15kg)
Given that mass of man is ![m=60kg](https://tex.z-dn.net/?f=m%3D60kg)
Initial velocity of ball = ![v_{i} = 10m/s](https://tex.z-dn.net/?f=v_%7Bi%7D%20%3D%2010m%2Fs)
Now considering momentum conservation
![p_{i} =p_{f}](https://tex.z-dn.net/?f=p_%7Bi%7D%20%3Dp_%7Bf%7D)
![m_{b}v_{i} = (m_{b} +m)\times v\\v=m_{b}v_{i}/(m_{b} +m) = \frac{150}{75} =2m/s](https://tex.z-dn.net/?f=m_%7Bb%7Dv_%7Bi%7D%20%3D%20%28m_%7Bb%7D%20%2Bm%29%5Ctimes%20v%5C%5Cv%3Dm_%7Bb%7Dv_%7Bi%7D%2F%28m_%7Bb%7D%20%2Bm%29%20%3D%20%5Cfrac%7B150%7D%7B75%7D%20%3D2m%2Fs)
<span>silicon (Si) had four valence electrons :)
</span>
Your answer is gonna be a velocity decreas of 10 meters per second
<h2>
Stopping force on the bullet is 1073.23 N to the left.</h2>
Explanation:
Mass of bullet, m = 11.0 g = 0.011 kg
Initial speed of bullet, u = 210 m/s
Final speed of bullet, v = 0 m/s
Displacement of bullet, s = 22.6 cm = 0.226 m
We have equation of motion v² = u² + 2as
Substituting
0² = 210² + 2 x a x 0.226
a = -97566.37 m/s²
We have
Force, F = Mass x Acceleration
F = 0.011 x -97566.37 = -1073.23 N
Negative means opposite to the direction of motion of bullet.
Stopping force on the bullet is 1073.23 N to the left.