The number in the photo should be the answer but the problem might just be that your question was worded incorrectly.
Answer: 81/100
Step-by-step explanation:
I don't guarantee you I am right but..
first, solve for the exponents after substituting the numbers in
3/5 x 3/5 is 9/25
since b's exponent is negative, you change the fraction into its reciprocal and then do it with the exponent but positive
2/3^-3 to 3/2^3 and 3/2 x 3/2 is 9/4
then you mutiply both numbers to get 9/4 x 9/25 is 81/100
Yes, because it is continuous on [0,2] and differentiable on (0,2), the theorem states that there must exist some value c where a line tangent to c is parallel to the secant line through 0 and 2.
Answer:
Step-by-step explanation:
Given a general quadratic formula given as ax²bx+c = 0
To generate the general formula to solve the quadratic equation, we can use the completing the square method as shown;
Step 1:
Bringing c to the other side
ax²+bx = -c
Dividing through by coefficient of x² which is 'a' will give:
x²+(b/a)x = -c/a
- Completing the square at the left hand side of the equation by adding the square of half the coefficient x i.e (b/2a)² and adding it to both sides of the equation we have:
x²+(b/a)x+(b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a + b²/4a²
- Taking the square root of both sides
√(x+b/2a)² = ±√-c/a + b²/√4a²
x+b/2a = ±√(-4ac+b²)/√4a²
x+b/2a =±√b²-4ac/2a
- Taking b/2a to the other side
x = -b/2a±√√b²-4ac/2a
Taking the LCM:
x = {-b±√b²-4ac}/2a
This gives the vertex form with how it is used to Solve a quadratic equation.
I’m pretty sure it’s c , sorry if it’s wrong tho
