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Eduardwww [97]
3 years ago
14

A bag is filled with green and blue marbles. There are 97 marbles in the bag. If there are 9 more green marbles than blue marble

s, find the number of green marbles and the number of blue marbles in the bag.
Mathematics
1 answer:
Alenkasestr [34]3 years ago
3 0

Answer:

44 blue and 52 green

Step-by-step explanation:


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The amount of tax for each camera is $5.25 and the tax rate is 6%. Explain how the equation: (Original Cost)(Percent) = Tax Amou
Degger [83]

x(1.06)=5.25

The reason it is 1.06 is because it is the original cost plus tax. You can divide each side by 1.06 to get x roughly equals 4.95.

So $4.95 is roughly what the camera costs rounded to the nearest cent.

3 0
4 years ago
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Which ordered pair is generated from the equation shown below? y = 3x + 2 A. (3, 11) B. (3, 9) C. (5, 15) D. (2, 4)
yan [13]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
If 30,000 cm2 of material is available to make a box with a square base and an open top, what is the largest possible volume (in
Cloud [144]

Answer:

The largest possible volume of the box is 2000000 cubic meters.

Step-by-step explanation:

The volume (V), in cubic centimeters, and surface area (A_{s}), in square centimeters, of the box with a square base are described below:

A_{s} = l^{2}+h\cdot l (1)

V = l^{2}\cdot h (2)

Where:

l - Side length of the base, in centimeters.

h - Height of the box, in centimeters.

By (2), we clear h within the formula:

h = \frac{V}{l^{2}}

And we apply in (1) and simplify the resulting expression:

A_{s} = l^{2}+ \frac{V}{l}

A_{s}\cdot l = l^{3}+V

V = A_{s}\cdot l -l^{3} (3)

Then, we find the first and second derivatives of this expression:

V' = A_{s}-3\cdot l^{2} (4)

V'' = -6\cdot l (5)

If V' = 0 and A_{s} = 30000\,cm^{2}, then we find the critical value of the side length of the base is:

30000-3\cdot l^{2} = 0

3\cdot l^{2} = 30000

l = 100\,cm

Then, we evaluate this result in the expression of the second derivative:

V'' = -600

By Second Derivative Test, we conclude that critical value leads to an absolute maximum. The maximum possible volume of the box is:

V = 30000\cdot l - l^{3}

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4 0
3 years ago
Can someone help me with this problem ​
Alex_Xolod [135]

Answer:

<h2>A = 20</h2><h2>P = 6√10</h2>

Step-by-step explanation:

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A(-3, 0) , B(3, 2)

AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}

A(-3, 0), D(-2, -3)

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AB = CD and AD = BC

The area of a rectangle:

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Substitute:

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Substitute:

P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}

4 0
3 years ago
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4 0
3 years ago
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