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ivanzaharov [21]
3 years ago
11

How many kilojoules are released when 2.25 mol of H2O2 reacts?

Chemistry
1 answer:
Stels [109]3 years ago
8 0

Answer:

230.3 kJ

Some chemical reactions show release of heat while some show absorption of heat. On these bases, the reaction is classified as either endothermic or exothermic. Negative sign of ΔH means exothermic reaction.

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The___ of an element is the number of
castortr0y [4]

Answer:atomic mass, neutrons in the nucleus

Explanation: because I remember from when I took honors chemistry last year we learned about this and it’s called the atomic mass when looking at an atom and the neutrons in the nucleus are effected by it.

8 0
3 years ago
How much sodium bicarbonate to raise alkalinity in pool.
almond37 [142]

Answer:

A rule of thumb is that 1.5 lbs. of baking soda per 10,000 gallons of water will raise alkalinity by about 10 ppm. If your pool's pH is tested below 7.2, add 3-4 pounds of baking soda. If you're new to adding pool chemicals, start by adding only one-half or three-fourths of the recommended amount.

4 0
2 years ago
Three beakers contain clear, colorless liquids. one beaker contains pure water, another contains salt water, and another contain
tiny-mole [99]
First, we'll identify the beaker containing pure water as follows:
We'll take equal masses from each of the three beakers and measure the mass of each.
We'll then identify the density of each by using the rule : density =mass/volume
Pure water will be the liquid having density equal to 1 gm/cm^3

Then, we'll differentiate between the salt and sugar solution by measuring the conductivity of each solution. Salt solution is a good conductor while solution of sugar is a bad conductor.
8 0
3 years ago
What is the full number for 5.7x10^4
dsp73

Answer:

5.7*10^4 is equal to 57,000.

Explanation:

First, we must multiply 10 by its power, 4. That would be 10 4 times.

10*10*10*10 = 10,000.

Then, we multiply it by 5.7.

5.7*10,000 = 57,000.

Regards!

3 0
3 years ago
Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. the initial temperature of the gas is 27.0c
Alla [95]

We have to know final temperature of the gas after it has done 2.40 X 10³ Joule of work.

The final temperature is: 75.11 °C.

The work done at constant pressure, W=nR(T₂-T₁)

n= number of moles of gases=6 (Given), R=Molar gas constant, T₂= Final temperature in Kelvin, T₁= Initial temperature in Kelvin =27°C or 300 K (Given).

W=2.4 × 10³ Joule (Given)

From the expression,

(T₂-T₁)=\frac{W}{nR}

(T₂-T₁)= \frac{2.40 X 10^{3} }{6 X 8.314}

(T₂-T₁)= 48.11

T₂=300+48.11=348.11 K= 75.11 °C

Final temperature is 75.11 °C.


6 0
3 years ago
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