Which compound that directly provides energy in living cells is being produced in every tube where cellular respiration is occur
1 answer:
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Explanation:
The given data is as follows.
No. of moles = , V = ?
T = 20.2 + 273 K = 293.2 K, P = = 1.046 atm, R =
Calculate the volume using ideal gas equation as follows.
P V = n R T
V =
=
= L
Thus, we can conclude that volume of the gas is L.
Answer:
3.80*10⁻³ moles of HCl can be produced from 0.226 g of SOCl₂
Explanation:
The balanced reaction is:
SOCl₂ + H₂O ----> SO₂ + 2 HCl
By stoichiometry of the reaction they react and produce:
- SOCl₂: 1 mole
- H₂O: 1 mole
- SO₂: 1 mole
- HCl: 2 mole
Being:
- S: 32 g/mole
- O: 16 g/mole
- Cl: 35.45 g/mole
- H: 1 g/mole
the molar mass of the compounds participating in the reaction is:
- SOCl₂: 32 g/mole + 16 g/mole + 2*35.45 g/mole= 118.9 g/mole
- H₂O: 2*1 g/mole + 16 g/mole= 18 g/mole
- SO₂: 32 g/mole + 2*16 g/mole= 64 g/mole
- HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
Then, by stoichiometry of the reaction, the following amounts of mass react and are produced:
- SOCl₂: 1 mole* 118.9 g/mole= 118.9 g
- H₂O: 1 mole* 18 g/mole= 18 g
- SO₂: 1 mole* 64 g/mole= 64 g
- HCl: 2 mole* 36.45 g/mole= 72.9 g
Then the following rule of three can be applied: if by stoichiometry of the reaction 118.9 grams of SOCl₂ produce 2 moles of HCl, 0.226 grams of SOCl₂ how many moles of HCl do they produce?
moles of HCl= 3.80*10⁻³
<u><em>3.80*10⁻³ moles of HCl can be produced from 0.226 g of SOCl₂</em></u>