Answer: 5
Explanation: 12(3) - 3(1/3)/4(3)-5
= 36-1/12-5
= 35/7
= 5
Answer:
2(x+2)
Step-by-step explanation:
Factor out the 2.
Answer:
The area of the base of the rectangular prism is:
- <u>18 square centimeters</u>.
The height of the rectangular prism is:
The volume of the rectangular prism is:
- <u>108 cubic centimeters</u>.
Step-by-step explanation:
To find the area of the base of the prism, you must remember that it corresponds to the rectangle formed by the points ABCD, with this in mind we apply the area formula that is equal to:
- Area of a rectangle = base * height.
Since the rectangle formed by the mentioned points has a base of 9 cm and a height of 2 cm, these values are the ones we use in the formula:
- Area of a rectangle = 9 cm * 2 cm
- <u>Area of a rectangle = 18 cm^2
</u>
Since the height requested by the second question is not from the rectangle at the base but from the entire prism, you should look at the height formed by the AW points, which as you can see is:
- <u>Prism height = 6 cm
</u>
Once we have these two data, it is very easy to calculate the volume since they are what we require in the volume formula:
- Volume = area * height.
- Volume = 18 cm^2 * 6 cm
- <u>Volume = 108 cm^3</u>
The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
Answer: Required expression: 
Result: 
Step-by-step explanation:
Given phrase: 
Required expression: ['+' used to express sum, 'x' used in place of 'of']
Since 18+16 = 34
Then,
![\dfrac14\times(18+16)=\dfrac14\times34 \\\\=\dfrac{1}{2}\times17\ \ \text{[Divide numerator and denominator by 2]}\\\\=\dfrac{17}{2}](https://tex.z-dn.net/?f=%5Cdfrac14%5Ctimes%2818%2B16%29%3D%5Cdfrac14%5Ctimes34%20%20%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes17%5C%20%5C%20%5Ctext%7B%5BDivide%20numerator%20and%20denominator%20by%202%5D%7D%5C%5C%5C%5C%3D%5Cdfrac%7B17%7D%7B2%7D)
Hence, 
