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2 years ago

What is the molar mass of CaCL2•2 H2O

Chemistry

1 answer:

kotykmax [81]2 years ago

6 0

Answer:

147 amu

Explanation:

CaCl2. 2H2O

=>40*1+35.5*2+2*1*2+2*16

=>40+71+4+32

=>147 amu..

I hope u will understand it:-):-)

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Aerosol cans have a label that warns the user not to use them above a certain temperature and not to dispose of them by incinera

Alex73 [517]

Answer:

1.40 atm

Explanation:

To answer this question we can use<em> Gay-Lussac's law</em>, which states:

P₁T₂=P₂T₁

When volume and number of moles remain constant.

P₁ = 1.11 atm

T₁ = 23°C ⇒ 23+273.16 = 296.16 K

T₂ = Boiling point of water = 100 °C ⇒ 100+273.16 = 373.16 K

P₂ = ?

We <u>put the known data in the equation and solve for P₂</u>:

1.11 atm * 373.16 K = P₂ * 296.16 K

P₂ = 1.40 atm

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2 years ago

A decomposition reaction has a half-life that does not depend on the initial concentration of the reactant.what is the order of

kupik [55]

The reaction is first order.

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2 years ago

For the reaction A +B+ C D E, the initial reaction rate was measured for various initial concentrations of reactants. The follow

lora16 [44]

Answer:

Rate constant of the reaction is $3.3\times 10^{-3} M^{-2} s^{-1}$ .

Explanation:

A + B + C → D + E

Let the balanced reaction be ;

aA + bB + cC → dD + eE

Expression of rate law of the reaction will be written as:

$R=k[A]^a[B]^b[C]^c$

Rate(R) of the reaction in trail 1 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.30 M$

$R=9.0\times 10^{-5} M/s$

$9.0\times 10^{-5} M/s=k[0.30 M]^a[0.30 M]^b[0.30 M]^c$ ...[1]

Rate(R) of the reaction in trail 2 ,when :

$[A]=0.30 M,[B]=0.30 M,[C]=0.90 M$

$R=2.7\times 10^{-4} M/s$

$2.7\times 10^{-4} M/s=k[0.30 M]^a[0.30 M]^b[0.90 M]^c$ ...[2]

Rate(R) of the reaction in trail 3 ,when :

$[A]=0.60 M,[B]=0.30 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.30 M]^b[0.30 M]^c$ ...[3]

Rate(R) of the reaction in trail 4 ,when :

$[A]=0.60 M,[B]=0.60 M,[C]=0.30 M$

$R=3.6\times 10^{-4} M/s$

$3.6\times 10^{-4} M/s=k[0.60 M]^a[0.60 M]^b[0.30 M]^c$ ...[4]

By [1] ÷ [2], we get value of c ;

c = 1

By [3] ÷ [4], we get value of b ;

b = 0

By [2] ÷ [3], we get value of a ;

a = 2

Rate law of reaction is :

$R=k[A]^2[B]^0[C]^1$

Rate constant of the reaction = k

$9.0\times 10^{-5} M/s=k[0.30 M]^2[0.30 M]^0[0.30 M]^1$

$k=\frac{9.0\times 10^{-5} M/s}{[0.30 M]^2[0.30 M]^0[0.30 M]^1}$

$k=3.3\times 10^{-3} M^{-2} s^{-1}$

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2 years ago

Las sustancias ionicas y los metale sson electricamente neutros. ¿como es esto posible si estan formados por iones, que posen ca

Anton [14]

Answer:

ver explicacion

Explanation:

Los iones se forman cuando las especies químicas pierden o ganan electrones.

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Los átomos de metal se mantienen unidos por el enlace metálico. Esto implica la interacción entre iones metálicos cargados positivamente y un mar de electrones negativos. Las cargas positivas de los iones metálicos están exactamente equilibradas por el mar de electrones cargados negativamente, por lo que el metal es neutro.

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Nadusha1986 [10]

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Learn more about chromatography:

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1 year ago