Answer : Both solutions contain molecules.
Explanation : The number of molecules of 0.5 M of sucrose is equal to the number of molecules in 0.5 M of glucose. Both solutions contain molecules.
Avogadro's Number is = which represents particles per mole and particles may be typically molecules, atoms, ions, electrons, etc.
Here, only molarity values are given; where molarity is a measurement of concentration in terms of moles of the solute per liter of solvent.
Since each substance has the same concentration, 0.5 M, each will have the same number of molecules present per liter of solution.
Addition of molar mass for individual substance is not needed. As if both are considered in 1 Liter they would have same moles which is 0.5.
We can calculate the number of molecules for each;
Number of molecules = ;
∴ Number of molecules = which will be =
Thus, these solutions compare to each other in that they have not only the same concentration, but they will have the same number of solvated sugar molecules. But the mass of glucose dissolved will be less than the mass of sucrose.
Answer:
Molarity = 0.5 M
Osmolarity = 0.5 x 2 = 1 Osmpl.
Molecules of Cl2 = 6.02 x / 4= 1.505 x no. of molecules
Explanation:
If we add half mole in 1L volume than molarity will obviously be 0.5 M.
The osmolarity is molarity multiplies by number of dissociates of solute that for CaCl2 are 2. So, 2 x 0.5 = 1
Half will be molecules of Ca and half will be of Cl2 for 0.5M.
Answer:
Dominant traits are traits that more likely to be transferred from a parent to an offspring so scientist use this term dominant.
CuSO₄ + 2NaOH → Cu(OH)₂ + Na₂SO₄
M(CuSO₄)=159.61 g/mol
m(CuSO₄)=638.44 g
n(CuSO₄)=m(CuSO₄)/M(CuSO₄)
n(CuSO₄)=638.44/159.61= 4.00 mol
M(NaOH)=40.00 g/mol
m(NaOH)=240.0 g
n(NaOH)=m(NaOH)/M(NaOH)
n(NaOH)=240.0/40.00= 6.00 mol
on the reaction equation
CuSO₄ : NaOH = 1 : 2
in practice
CuSO₄ : NaOH = 4 : 6 = 1 : 1.5 ⇒ NaOH is the limiting reactant