Answer is: <span>edge of the length of the box measured is 1280,57 kilometers.
</span>V(raindrop) = 3,48 cm³.
V(cubic box) = 3,48 cm³ · 6,023·10²³.
V(cubic box) = 2,1·10²⁴ cm³.
V(cubic box) = 2,1·10²⁴ cm³ ÷ 10¹⁵.
V(cubic box) = 2,1·10⁹ km³.
r(cubic box) = ∛2,1·10⁹ km³.
r(cubic box) = 1280,57 km.
Answer:
C = 107.97 mol/L
Explanation:
Given data:
Volume of solution = 1.38 mL (1.38 mL× 1 L /1000 mL = 0.00138 L)
Mass of ammonium sulfite = 17.36 g
Concentration of solution =?
Solution:
We will calculate the number of moles of ammonium sulfite.
Number of moles = mass/molar mass
Number of moles = 17.36 g / 116.15 g/mol
Number of moles = 0.149 mol
Concentration:
C = n/V
C = concentration
n = number of moles of solute
v = volume in L
C = 0.149 mol / 0.00138 L
C = 107.97 mol/L
Ca(OH)2 (aq) because of elements oxygen and hydrogen
