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3 years ago

Mg + 2H20 + Mg(OH)2 + H2 + 353kJ

Chemistry

1 answer:

mixer [17]3 years ago

7 0

Answer:

$m_{H_2O}=8.9g$

Explanation:

Hello,

Based on the given reaction, since magnesium and water are in a 1:2 molar ratio at the reactants, we must apply the following stoichiometric factors to compute the complete reaction of the 6.0 g of magnesium:

$m_{H_2O}=6.0gMg*\frac{1molMg}{24.305 gMg}*\frac{2molH_2O}{1molMg} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=8.9g$

Best regards.

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