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3 years ago

Balance the following chemical equation.

Chemistry

1 answer:

andrew-mc [135]3 years ago

6 0

Answer:

A. 3Mg + N₂ → Mg₃N₂

Explanation:

This is a multiple choice question, so the correct answer is in one of the options.

A. is correct. It has three atoms of Mg and two of N on each side of the equation.

B. is wrong. It has four atoms of N on the left and two on the right.

C. is wrong. It has six atoms of Mg on the left and nine on the right.

D. is wrong. It has one atom of Mg on the left and three on the right.

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What will i observe when i bring the elrctro magnet near to some aluminum clips?

Llana [10]

Hey mate here is ur ans
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3 years ago

In Rutherford's Gold foil experiment, were the alpha particles directed to different areas of the gold foil or only the same spo

MrRissso [65]

Answer:

See explanation

Explanation:

In the Rutherford experiment, alpha particles were directed at the same spot on a thin gold foil.

As the alpha particles hit the foil, most of the alpha particles went through the foil. In Rutherford's interpretation, most of the particles went through because the atom consisted largely of empty space.

However, some of the alpha particles were deflected through large angles, in Rutherford's interpretation, the deflected alpha particles had hit the dense positive core of the atom which he called the nucleus.

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3 years ago

The geological era about which we have the least information is called _____.

iVinArrow [24]

Cretaceous Period.............

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3 years ago

Read 2 more answers

What mass of carbon dioxide is produced from the complete combustion of 4.50×10−3 g of methane?

ivanzaharov [21]

CH₄ + 2O₂ → CO₂ + 2H₂O

From the equation, we know that methane and carbon dioxide have the same number of moles.

$no. of moles = \frac{mass}{molar mass}$

no. of moles of CO₂ produced = no. of moles of methane

= 4.5 × 10⁻³ ÷ (12 + 1×4)

= 2.8125 × 10⁻⁴

∴ mass of CO₂ = 2.8125 × 10⁻⁴ × (12 + 16×2)

= 12.375 × 10⁻³ g

4 0

3 years ago

Question:<br> What is the molar concentration of 1.29 mol of KCL dissolved in 350 mL of solution?

STatiana [176]

Answer:

M = 3.69 M.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the molar concentration of the 1.29 moles of KCl in 350 mL of solution by recalling the mathematical definition of molarity as the division of the moles by the volume in liters, in this case 0.350 L; thus, we proceed as follows:

$M=\frac{1.29mol}{0.350L}\\\\M=3.69M$

Which gives molar units, M, or just mol/L.

Regards!

8 0

3 years ago