The mass of CO₂ gas = 4.312 g
<h3>Further explanation</h3>Reaction
NaHCO₃ (s) + HCl (aq) → NaCl (aq) + H₂O (aq) + CO₂ (g)
Find limiting reactant
mol NaHCO₃
mol HCl
Limiting reactant : NaHCO₃ (smaller)
mol CO₂ = mol NaHCO₃ = 0.098
mass CO₂ :
Balance the following chemical equation.
1 answer:
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Answer: Theoretical yield of produced by 8.96 g of S is 33.6 g
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
2 moles of produce = 3 moles of
Thus 0.28 moles of will produce=
of
Mass of
Thus theoretical yield of produced by 8.96 g of S is 33.6 g
Answer:
wait I AM TRYING..................
this is limiting reactant
