Density = 1.0 g/mL
5.3 (w/w)% => 5.3 / 100 => 0.053
molar mass acetic acid = 60.05 g/mol
M = 1000. w . D / molar mass
M = 1000 . 0.053 . 1.0 / 60.05
M = 53 / 60.05
M = 0.882 mol/L
hope this helps!
They would have to dispose them in their designated waste bin/container the instructor assigned.
You NEVER dispose of chemicals down the drain.
Answer:
The wood is oak.
Explanation:
Given data:
Mass of wood = 70 g
Volume of wood = 103 cm³
Wood is oak = ?
Solution:
We will calculate the density of wood then we will compare it with literature value.
Density = mass/ volume
d = 70 g/ 103 cm³
d = 0.68 g/cm³
The density of oak is 0.59 - 0.90 g/cm³.
So its true, wood is oak.
Answer:
a) KOH
Explanation:
In the given balanced reaction
2K + 2H2O → 2KOH + H2
In the compound KOH,
The elements are K,O, and H and in the compound, there is one mole each of K , O ,and H.
So the element ratio here is 1 : 1 : 1.
