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Alex17521 [72]
3 years ago
15

Use graphing to find the solution of the system of equations. -x^2+y=1, -x+y=2

Mathematics
1 answer:
vladimir2022 [97]3 years ago
5 0

ANSWER


x=-0.62 or x=1.62




EXPLANATION


For -x^2+y=1



We make y the subject to obtain,



y=x^2+1


We can easily graph this function, because we just have to transform the graph of y=x^2 by shifting the intercept up to 1.



As for the straight line, -x+y=2,


We find the intercepts as follows,



When y=0,x=-2.


When x=0,y=2.


We plot the points (-2,0) and


(0,2).



We now draw the two graphs on the same graph sheet. The intersection of the two graphs gives the solution to be


x=-0.62 or x=1.62


See graph




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======================================================

Reason:

Let's find the distance from A to B. This is equivalent to finding the length of segment AB. I'll use the distance formula.

A = (x_1,y_1) = (3,5) \text{ and } B = (x_2, y_2) = (7,6)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(3-7)^2 + (5-6)^2}\\\\d = \sqrt{(-4)^2 + (-1)^2}\\\\d = \sqrt{16 + 1}\\\\d = \sqrt{17}\\\\d \approx 4.1231\\\\

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If you were to repeat similar steps for the other sides (BC, CD and AD) you should find that all four sides are the same length. Because of this fact, we have a rhombus.

-------------------------

Let's see if this rhombus is a square or not. We'll need to see if the adjacent sides are perpendicular. For that we'll need the slope.

Let's find the slope of AB.

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We don't have perpendicular lines, so the interior angles are not 90 degrees each.

Therefore, this figure is not a rectangle and by extension it's not a square either.

The best description for this figure is a <u>rhombus</u>.

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