Equation is as follow,
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
Oxidation:
3 CO → 3 CO₂
Oxidation state of C in CO is +2, and that in CO₂ is +4. So, carbon has lost 2 electrons per mole and 6 electrons per 3 moles hence,
3 CO → 3 CO₂ + 6 e⁻
Reduction:
Fe₂O₃ → 2 Fe
Oxidation state of Fe in Fe₂O₃ is +3 per atom, and that in Fe is 0. So, Iron has gained 3 electrons per atom and 6 electrons per 2 atoms hence,
Fe₂O₃ + 6e⁻ → 2 Fe
Result:
Iron in Fe₂O₃ has been reduced in this reaction and has played a role of oxidizing agent by oxidizing carbon from +2 state to +4 state.
Answer:
Explanation:
Froath flotaion process is based on thie wttebality properteis like hydrophillicity and hydrophobicity.
Incase of sulphide ore processing,
The metallic sulphide particles of ore are preferentially wetted by oil and the gangue particles by water. By doing thise you are sperating required sulphide ore particels from unwanted gaunge , by doing this you are incresing the concentation of Sulfide in ore by removing the not required gaunge particles.
Hope this helps you to decide your annswer
Answer:
615 g
Explanation:
In order to convert from moles of any given substance into grams, we have to use said substance's <em>molar mass</em>, as follows:
- # moles * Molar mass = grams of substance.
Thus, we now <u>calculate the molar mass of beryllium iodide</u>, BeI₂, using the <em>molar masses of the elements</em>:
- Molar Mass of BeI₂ = Molar Mass of Be + (Molar Mass of I)*2 = 262.821 g/mol
Finally we <u>calculate how many grams are there in 2.34 moles of BeI₂</u>:
- 2.34 mol * 262.821 g/mol = 615 g
