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sesenic [268]
3 years ago
11

If the density of ocean water at a depth of 1.00 x 104 m is 1.071 g/mL and if 26.0 g of water at that depth contains 182mg of po

tassium chloride, what is the molarity of potassium chloride in the sample?

Chemistry
2 answers:
sammy [17]3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

LenKa [72]3 years ago
4 0

Answer:

Molarity of potassium chloride is 0.100M

Explanation:

Molarity is defined as moles of solute per liter of solvent.

Moles of solute (Potassium chloride; MW: 74.55g/mol):

0.182g × (1mol / 74.55g) = <em>2.44x10⁻³mol KCl</em>

<em />

Liters of water using density are:

26.0g Water × ( 1mL / 1.071g) × (1L / 1000mL) = <em>0.0243L</em>

<em />

Thus, molarity of KCl in the sample is:

<em>2.44x10⁻³mol KCl / 0.0243L = </em><em>0.100M</em>

<em />

I hope it helps!

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Answer:

I would assume NON-METALS

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3 years ago
4NH3 + 3O2 --&gt; 2N2 + 6H2O
larisa86 [58]

The balanced reaction is:

4NH3 + 3O2 --> 2N2 + 6H2O

 <span>We are given the amount of reactants to be used for the reaction. This will be the starting point of our calculation.</span>

83.7g of O2 ( 1 mol / 32 g) = 2.62 mol O2

2.81 moles of NH3

From the balanced reaction, we have a 4:3 ratio of the reactants. The limiting reactant would be oxygen. We will use the amount for oxygen for further calculations.

<span>2.62 mol O2</span><span> (6 mol H2O  / 3 mol O2) (18.02 g H2O / 1 mol H2O) = 94.42 g H2O</span>

8 0
2 years ago
For the reaction PC15 (8) PC13 (g) + Cl2 (g) K = 0.0454 at 261 °C. If a vessel is filled with these gases such that the initial
Fiesta28 [93]

Answer:

The correct answer is B.

The K_{eq} is samller than Q of the reaction . So,the reaction will shift towards the left i.e. towards the reactant side.

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

K is the constant of a certain reaction when it is in equilibrium, while Q is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)

The expression for Q is written as:

Q=\frac{[PCl_3][Cl_2]}{[[PCl_5]^1}

Q=\frac{0.20 M\times 2.5 M}{0.20 M}

Q=2.5

Given : K_{eq} = 0.0454

Thus as K_{eq}, the reaction will shift towards the left i.e. towards the reactant side.

4 0
3 years ago
Read 2 more answers
A potassium-40 sample starts with 50 atoms, and 1.25 billion years later, there are 25 atoms. What is the half-life of potassium
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3 years ago
Rank the compounds in each set in order of increasing acid strength.
Viktor [21]

Answer:

See explanation

Explanation:

For this question, we have to remember the effect of an atom with high <u>electronegativity</u> as "Br". If the "Br" atom is closer to the carboxylic acid group (COOH) we will have an <u>inductive effect</u>. Due to the electronegativity of Br, the electrons of the C-H bond would be to the Br, then this bond would be <u>weaker</u> and the compound will be more acid (because is easier to produce the hydronium ion H^+).

With this in mind, for A in the last compound, we have <u>2 Br atoms</u> near to the acid carboxylic group, so, we will have a high inductive effect, then the C-H would be weaker and we will have <u>more acidity</u>. Then we will have the compound with only 1 Br atom and finally, the last compound would be the one without Br atoms.

In B, the difference between the molecules is the <u>position</u> of the "Br" atom in the molecule. If the Br atom is closer to the acid group we will have a <u>higher inductive effect</u> and more <u>acidity</u>.

See figure 1

I hope it helps!

5 0
3 years ago
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