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gavmur [86]
3 years ago
13

Help me with assigment please

Chemistry
1 answer:
vesna_86 [32]3 years ago
8 0

Answer: I belive the answer is A

Explanation:

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Balancing Al+ Agcl, i have problems with this so help!!!
EleoNora [17]

Answer:

Al  + 3AgCl  →  AlCl₃  + 3Ag

Explanation:

The given equation is:  

      Al  + AgCl  →  

We are to find the product and hence balance the equation. This problem is a simple single replacement reaction.

By virtue of this, Aluminum will displace Ag from the solution:

                       Al  + AgCl  →  AlCl₃  + Ag

    We then balance the equation:

                        Al  + 3AgCl  →  AlCl₃  + 3Ag

                                             

5 0
3 years ago
Which of the following are good conductors
dimulka [17.4K]

Answer:

iron, graphite,NaCl solution etc are some examples of good conductor of electricity

5 0
2 years ago
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Rick has taken a loan of $3,200 from the bank to buy new appliances. His first loan payment is due at the end of this month. He
marysya [2.9K]

Answer:

140

Explanation:

4 0
3 years ago
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How many moles are in 43.9 L of oxygen
Ede4ka [16]

Answer: 2 mol

Explanation:

- According to the ideal gas law, One mole of an ideal gas at STP (standard temperature and normal pressure) occupies 22.4 liters.

- Using cross multiplication,

                               1 mol of (O2)        →       22.4 L

                                       ?                   →        43.9 L

Therefore, the number of moles of oxygen in 43.9 L = (43.9 × 1)/ 22.4 = 1.96 mol≈ 2 mol..


3 0
2 years ago
Calculate the mass of butane needed to produce 97.4 g of carbon dioxide. Express your answer to three significant figures and in
Vsevolod [243]

Answer:

32.1 g

Explanation:

Step 1: Write the balanced combustion reaction

C₄H₁₀ + 6.5 O₂ ⇒ 4 CO₂ + 5 H₂O

Step 2: Calculate the moles corresponding to 97.4 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

97.4 g × 1 mol/44.01 g = 2.21 mol

Step 3: Calculate the moles of butane that produced 2.21 moles of carbon dioxide

The molar ratio of C₄H₁₀ to CO₂ is 1:4. The moles of C₄H₁₀ required are 1/4 × 2.21 mol = 0.553 mol

Step 4: Calculate the mass corresponding to 0.553 moles of C₄H₁₀

The molar mass of C₄H₁₀ is 58.12 g/mol.

0.553 mol × 58.12 g/mol = 32.1 g

4 0
3 years ago
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