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gavmur [86]
3 years ago
13

Help me with assigment please

Chemistry
1 answer:
vesna_86 [32]3 years ago
8 0

Answer: I belive the answer is A

Explanation:

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The alkali earth metal beryllium (Be) engages in a chemical reaction and loses all of its valence electrons.
denpristay [2]

The loss of electron from an results in the formation of cation represented by the positive charge on the element whereas gaining of electron results in the formation of anion represented by the negative charge on the element.

The alkali earth metal beryllium (Be) belongs to the second group of the periodic table. The ground state electronic configuration of Be is:1s^{2}2s^{2}

From the electronic configuration it is clear that it has 2 valence electrons in its valence shell (2s^{2}).

After losing all valence electrons that is 2 electrons from 2s orbital. The electronic configuration will be:

1s^{2}2s^{0}

Since, lose of electron is represented by positive charge on the element symbol. So, the beryllium will have +2 charge on its symbol as Be^{2+}.

Hence, beryllium will have 2+ charge on it after losing all its valence electrons in the chemical reaction.

6 0
3 years ago
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It takes______ dekaliters to make 100 L.<br><br> A.1000<br> B.1<br> C.10<br> D.0.1
otez555 [7]

Answer:

c

Explanation:

7 0
2 years ago
For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [
sveta [45]

Explanation:

The given data is as follows.

     E^{o} = 0.483,     [Co^{3+}] = 0.173 M,

     [Co^{2+}] = 0.433 M,     [Cl^{-}] = 0.306 M,

     P_{Cl_{2}} = 9.0 atm

According to the ideal gas equation, PV = nRT

or,             P = \frac{n}{V}RT    

Also, we know that

                Density = \frac{mass}{volume}

So,         P = MRT

and,          M = \frac{P}{RT}

                    = \frac{9.0 atm}{0.0820 L atm/mol K \times 298 K}

                    = \frac{9.0}{24.436}

                    = 0.368 mol/L

Now, we will calculate the cell potential as follows.

          E = E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}

             = 0.483 - \frac{0.0591}{2} log \frac{(0.433)^{2}(0.368)}{(0.173)(0.306)^{2}}

             = 0.483 - 0.02955 log \frac{0.0689}{0.0162}

             = 0.483 - 0.02955 \times 0.628

             =  0.483 - 0.0185

             = 0.4645 V

Thus, we can conclude that the cell potential of given cell at 25^{o}C is 0.4645 V.

4 0
3 years ago
PLZ HELP!!!!
d1i1m1o1n [39]

Answer:

I agreeee

Explanation:

5 0
3 years ago
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the grade of coal increases with (remember a higher grade of coal means it produces more energy when burned) quizlet
Aleks04 [339]

The grade of coal increases with compaction.

<h3>What is Compaction?</h3>

When something is crushed or compressed, it becomes compacted. After being collected, trash is often compressed to make it smaller and take up less room. Compaction is the process of making anything more compact, dense, or firmly packed.

grade of coal - The highest grade of coal is anthracite. It is a black, glossy, hard, brittle coal that is frequently referred to as hard coal. It has a high proportion of fixed carbon and a low proportion of volatile matter. Between subbituminous and anthracite, bituminous coal is the intermediate rank of coal.

to learn more about  compaction go to -

brainly.com/question/2837181

#SPJ4

5 0
1 year ago
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