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3 years ago

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Help me with assigment please

1 answer:

vesna_86 [32]3 years ago

8 0

Answer: I belive the answer is A

Explanation:

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Which of the following does not state a property of electricity?

vagabundo [1.1K]

D, It is a flow of protons, is the best answer. Electricity is the flow of electrons, not protons.

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2 years ago

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How many grams of carbon are present in 45.0 g of CCl4?

lisabon 2012 [21]

To determine the amount of a certain element in a compound, we use the ratio of the elements from the compound. We calculate is follows:

45.0 g CCl4 ( 1 mol CCl4 / 153.82 g CCl4 ) ( 1 mol C / 1 mol CCl4 ) ( 12.01 g C / 1 mol C ) = 3.5135 g carbon present

Hope this answers the question. Have a nice day.

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3 years ago

The chemical formula of ordinary sugar is C12H22O11. Calculate the mass of 7.35 mol of sugar.

ch4aika [34]

First, you need to find the mass of 1 mol of sugar. Mass, or molar mass, can simply be found by adding the masses of the individual elements. These are given to you on the periodic table.

$C_{12}H_{22}O_{11}$

12 x 12.011 grams (molar mass of Carbon) = 144.132 g

22 x 1.008 grams (molar mass of Hydrogen) = 22.176 g

11 x 15.999 grams (molar mass of Oxygen) = 175.989 g

Add all of the pieces together.

144.132 g + 22.176 g + 175.989 g = 342.297 grams

So, if one mole has 342.297 grams, then 7.35 of that amount will be your answer.

342.297 g/mol x 7.35 mol = 2,515.88 grams

7 0

2 years ago

A solid is 5 cm tall, 3 am wide, and 2 cm thick. It has a mass of 135 g. What is the solid's density?

gizmo_the_mogwai [7]

<u>Answer:</u>

density of solid = 4.5 g/cm³

<u>Explanation:</u>

density = mass ÷ volume

• We know the mass of the object (135 g). We need to calculate the volume:

Volume = length × width × thickness

= 5 cm × 3 cm × 2 cm

= 30 cm³

• Now we can calculate the solid's density:

density = 135 g ÷ 30 cm³

= 4.5 g/cm³

4 0

1 year ago

Calculate the volume of 0.100 m hcl required to neutralize 1.00 g of ba(oh)2 (molar mass = 171.3 g/mol).

dedylja [7]

The balanced chemical equation between HCl and $Ba(OH)_{2}$ is:

$2HCl (aq) + Ba(OH)_{2}(aq) -->BaCl_{2}(aq) + 2 H_{2}O(l)$

Moles of $Ba(OH)_{2}$ = $1.00 g Ba(OH)_{2} * \frac{1 mol Ba(OH)_{2}}{171.3 g Ba(OH)_{2}} = 0.00584 mol Ba(OH)_{2}$

Moles of HCl required to neutralize $Ba(OH)_{2}$ :

$0.00584 mol Ba(OH)_{2} * \frac{ 2 mol HCl}{1 mol Ba(OH)_{2}} = 0.01168 mol HCl$

Calculating the volume of HCl from moles and molarity:

$0.01168 mol HCl * \frac{1 L}{0.100 mol} * \frac{1000 mL}{1 L} = 116.8 mL$

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2 years ago

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