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belka [17]
3 years ago
15

John runs 500 feet in 1 minute. Identify the correct conversion factor setup required to compute John's speed in inches per seco

nd.
Mathematics
2 answers:
slavikrds [6]3 years ago
7 0

Answer:

see the procedure

Step-by-step explanation:

Remember that

1\ ft=12\ in

To convert feet to inches multiply by 12

1\ min=60\ sec

To convert minutes to seconds multiply by 60

we have

500\frac{ft}{min}=500(\frac{12}{60})=500(\frac{1}{5})=100\frac{in}{sec}

Ivanshal [37]3 years ago
5 0

Answer:

\frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}

Step-by-step explanation:

We have been given that John runs 500 feet in 1 minute. We are asked to identify the correct conversion factor setup required to compute John's speed in inches per second.              

We know that 1 minute equals 60 seconds and 1 feet equals 12 inches .

\frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}

Therefore, our required conversion factor would be \frac{500\text{ ft}}{\text{ 1 min}}\times \frac{1 \text{ min}}{\text{ 60 sec}}\times \frac{12\text{ inches}}{\text{1 ft}}.  

Let us covert 500 feet in 1 minute to inches per second as:

\frac{500}{1}\times \frac{1}{\text{ 60 sec}}\times \frac{12\text{ inches}}{1}

\frac{500}{1}\times \frac{1}{\text{ 5 sec}}\times \frac{1\text{ inches}}{1}

\frac{500\text{ inches}}{\text{ 5 sec}}

\frac{100\text{ inches}}{\text{ sec}}

Therefore, John runs at a rate of 100 inches per second.

   

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