PV = nRT. Where P = pressure, V = volume, n = number of moles, R = universal gas constant and T = temperature. Hope this helps!
Answer:
M₂ = 0.0745 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = 0.0952 M
V₁ = 38.73 mL
M₂ = ?
V₂ = 49.48 mL
Using the above formula , the molarity of ammonia , can be calculated as ,
M₁V₁ = M₂V₂
0.0952 M * 38.73 mL = M₂* 49.48 mL
M₂ = 0.0745 M
Its a snake. snakes have lungs and a foot but no legs. its offspring are in eggs
Moles of Carbon dioxide : 0.75
<h3>Further explanation</h3>
Given
23 g C₃H₈O₃
Required
Moles of Carbon dioxide
Solution
Reaction
2C₃H₈O₃ + 7O₂ → 6CO₂ + 8H₂O
mol C₃H₈O₃ :
= mass : MW
= 23 g : 92,09382 g/mol
= 0.24975
From the equation, mol ratio of C₃H₈O₃ : 3CO₂ = 1 : 3, so mol CO₂ :
= 3/1 x mol C₃H₈O₃
= 3/1 x 0.24975
= 0.74925≈0.750 mol
