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Tom [10]
3 years ago
11

Control variables are parts of the experiment that you try to:

Chemistry
2 answers:
Katena32 [7]3 years ago
6 0

Answer:

A control variable in scientific experimentation is an experimental element which is constant and unchanged throughout the course of the investigation.

Hope this helped :)

maks197457 [2]3 years ago
3 0

Answer:

study, you do not change them as they are meant to be controls not like independent variables.

Explanation:

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A chef is serving a lunch special with 1 sandwich and 2 corn cobs per plate. If there are 5 sandwiches and 14 corn cobs, what is
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5 plates is the highest amount that can be served

There’s only 5 sandwiches so 7 is automatically ruled out, there’s 14 corn cobs and 5 sandwiches only need 10 so it works out
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The is the rate which a substance undergoes a chemical change
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Reaction Rate is the rate at which a substance undergoes a chemical change.

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Calculate the concentration of an aqueous solution of naoh that has a ph of 11.50
Reika [66]
NaOH is a strong base and complete dissociation into Na⁺ and OH⁻ ions. 
Therefore [NaOH] = [OH⁻]
To calculate the [OH⁻], we can first find the pOH as NaOH is a basic solution.
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pOH = 14 - 11.50
pOH = 2.50
We can calculate [OH⁻] by knowing pOH 
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[OH⁻] = antilog(-pOH)
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3 years ago
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34g aluminum are combined with 39g chlorine gas which is the limiting reactant
vampirchik [111]

The limiting reactant is chlorine (Cl2).

<u>Explanation</u>:

Limiting reactant is the amount of product formed which gets limited by the reagent without continuing it.

        2 Al + 3 Cl2 ==> 2 AlCl3  represents the balanced equation.

Number of moles Al present = 34 g Al x 1 mole Al / 26.98 g

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Number of moles Cl2 present = 39 g Cl2 x 1 mole Cl2 / 35.45 g

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Dividing each reactant by it's coefficient in the balanced equation obtains:

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The reactant which produces a lesser amount of product is called as limiting reactant.

Here the Limiting reactant is Cl2.

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What is true about the element calcium(Ca, atomic number 20)? Choose all that apply.
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It has 2 valence electrons

THANK ME
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