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MArishka [77]
3 years ago
15

Watch the video to determine which of the following relationships correctly depict the relationship between pressure and volume

for a fixed amount of gas at constant temperature according to Boyle’s law.
A. PV∝ P
B.V∝ 1P
C. P∝ 1V
D. PV∝ V
E. P∝ V
F. V∝ P
Chemistry
1 answer:
AnnZ [28]3 years ago
5 0

Answer : The correct options are,

(B) V\propto \frac{1}{P}

(C) P\propto \frac{1}{V}

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

V\propto \frac{1}{P}

The relation between the pressure and volume of two gases are:

P_1V_1=P_2V_2

where,

P_1 = initial pressure of gas

P_2 = final pressure of gas

V_1 = initial volume of gas

V_2 = final volume of gas

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A 35.0-ml sample of 0.150 m acetic acid (ch3cooh) is titrated with 0.150 m naoh solution. calculate the ph after 17.5 ml of base
Gekata [30.6K]
When the moles of CH3COOH = volume of CH3COOH * no.of moles of CH3COOH
moles of CH3COOH = 35ml * 0.15 m/1000 =0.00525 mol
moles of NaOH = volume of NaOH*no.of moles of NaOH
                           = 17.5 ml * 0.15/1000 = 0.002625
SO the reaction after add the NaOH:
                           CH3COOH(aq) +OH- (aq) ↔ CH3COO-(aq) +H2O(l)
initial                  0.00525                0                         0
change             - 0.002625         +0.002625     +0.002625
equilibrium      0.002625             0.002625        0.002625
When the total volume = 35ml _ 17.5ml = 52.5ml = 0.0525L
∴[CH3COOH] = 0.002625/0.0525 = 0.05m
and [CH3COO-]= 0.002625/0.0525= 0.05 m
when PKa = -㏒Ka
                 = -㏒1.8x10^-5 = 4.74
by substitution in the following formula:
PH = Pka + ㏒[CH3COO-]/[CH3COOH]
      = 4.74 + ㏒(0.05/0.05) = 4.74
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Weather balloon is filled with 62.3 L of helium gas at 760 mm of Hg after being released the volume increases to 130 L as the ba
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Answer : The pressure at this new altitude is, 364.2 mmHg

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

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Now put all the given values in the above equation, we get:

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