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Llana [10]
2 years ago
12

How much would 300 invested at 9 interest compounded continuously be worth after 3years

Mathematics
1 answer:
defon2 years ago
8 0

Answer: 392.99


Step-by-step explanation: Starting Principal: 300

Interest Rate: 9

   

Years: 3

Then solve


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Create a system of equations to solve
antiseptic1488 [7]
R=2K which equals 2R=4K
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Subtract first equation from second equation.
2R=32 so R=16

Plug into first equation
16=2K so K=8

Now plug both into second equation to check
4R-4K=4(R-K)=4(8)=32 it works

So Roberto is 16 and Katie is 8
(In 4 years R would be 20 and K would be 12 which has a difference of 8)
6 0
3 years ago
Calculate the simple interest for amount below.<br> $5500 at 5% for 6.5 years
snow_tiger [21]

Answer:

$7,287.50

Step-by-step explanation:

Use the formula A=P(1+rt), where P is the starting amount, R is the rate in %, and T is the time in years.

6 0
2 years ago
Read 2 more answers
Y= -7x-2<br> y+ 3 = -7x + 1<br> (<br> 2,3)<br> no solution<br> an infinite number of solutions
Naya [18.7K]

Answer:

Infinite number of solutions.

Step-by-step explanation:

y = -7x - 2

y + 3 = -7x + 1

Subtract 3 from both sides:

y = -7x - 2

- this is the same as the first equation.

We can put any number of valid combinations of x and y into this equation.

So there are infinite solutions.

8 0
3 years ago
how do you solve this: the sale price is $146.54 and the discount is 15% off. how do you solve for the original price?
N76 [4]
Mp. 146.54
dis . 15%
sp= 146.54 - 15 % of 146.54
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6 0
3 years ago
Tell whether the expressions in each pair are equivalent:p(4-4) and 0
kifflom [539]
P(4-4)=p(0)=0
0=0
true, they are equivilent
7 0
3 years ago
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