Step-by-step explanation:Step 1: Simplify both sides of the equation.
8(2x+3x+2)=−4x+148
(8)(2x)+(8)(3x)+(8)(2)=−4x+148(Distribute)
16x+24x+16=−4x+148
(16x+24x)+(16)=−4x+148(Combine Like Terms)
40x+16=−4x+148
40x+16=−4x+148
Step 2: Add 4x to both sides.
40x+16+4x=−4x+148+4x
44x+16=148
Step 3: Subtract 16 from both sides.
44x+16−16=148−16
44x=132
Step 4: Divide both sides by 44.
44x
44
=
132
44
x=3
answer: x=3
The smallest number of schools would be if all the schools entered the max amount of teams they could. So we first just want to say as many schools as possible entered 4 teams.
So here just divide 247 by 4.
That would be 61 R3
So we say that 61 schools entered with four teams. Now there are 3 teams extra. We can assign these to just one school, because a school can enter 3 teams. So then the total amount of schools entered in the XYZ contest, in this case, would be 62.
Answer:
A and D are the true number sentences
Answer:
B
Step-by-step explanation:
The formula for finding the relationship between a secant and a tangent is
tangent length ^2 = external segment secant/full length of secant
In this case
60^2 = 48*(x + 48) Expand
3600 = 48*(x + 48) Remove the brackets/
3600 = 48x + 48^2 Expand
3600 = 48x + 2304 Subtract 2304 from both sides
3600 - 2304 = 48x
1296 = 48x Divide both sides by 48
1296 / 48 = x
x = 27