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vazorg [7]
2 years ago
14

What is the slope of y-9=3(x-2) A. 3 B. 1/2 C. 2 D. 1/9

Mathematics
2 answers:
pav-90 [236]2 years ago
8 0

Answer:

A. 3

Step-by-step explanation:

y - 9 = 3(x-2)

y = 3x - 6 + 9

y = 3x + 3

slope is 3x = 3

d1i1m1o1n [39]2 years ago
5 0
A 3x is the correct answer
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Natalie has 412 apples that she must package into bags. Each bag must hold 8 apples. Natalie divides 412 by 8 and gets an answer
worty [1.4K]

Answer:

Natalie has 4 apples left

Step-by-step explanation:

one bag is 8 apples and only has 4 left so it cant fill another bag let alone 4, so a is out. Natalie has 4 apples, not 4 bags, so there goes B. The only one left is C Natalie has  apples left after filling 51 bags.

5 0
2 years ago
Kayla and Camille, both teachers, are adding books to their class libraries. Kayla’s classroom started out with a collection of
Airida [17]
34
because, 34 = 14 + (10 x 2)
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4 0
3 years ago
Could someone help me please?
fenix001 [56]

Answer:

a. 7.2

b. 6

Step-by-step explanation:

Since the side lengths of similar polygons are proportional to each other, therefore:

\frac{b}{10} = \frac{9}{15} = \frac{a}{12}

Thus, let's find b using:

\frac{b}{10} = \frac{9}{15}

Cross multiply

b*15 = 10*9

15b = 90

Divide both sides by 15

b = 6

Let's find a using:

\frac{9}{15} = \frac{a}{12}

Cross multiply

9*12 = 15*a

108 = 15a

Divide both sides by 15

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5 0
2 years ago
Please help what is the answer?​
MrRissso [65]

Answer:

The area of the shape is 18cm^2

Step-by-step explanation:

7 0
3 years ago
Which two values of x are roots of the polynomial below?<br> 3x2-3x+1
QveST [7]

Answer:

The roots are

x=\frac{1}{6} [3+ i\sqrt{3}]

x=\frac{1}{6} [3- i\sqrt{3}]

Step-by-step explanation:

we have

3x^2-3x+1

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^2-3x+1=0  

so

a=3\\b=-3\\c=1

substitute in the formula

x=\frac{-(-3)\pm\sqrt{-3^{2}-4(3)(1)}} {2(3)}

x=\frac{3\pm\sqrt{-3}} {6}

Remember that

i=\sqrt{-1}

so

x=\frac{1}{6} [3\pm i\sqrt{3}]

The roots are

x=\frac{1}{6} [3+ i\sqrt{3}]

x=\frac{1}{6} [3- i\sqrt{3}]

6 0
2 years ago
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