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Nitella [24]
3 years ago
7

An object can have forces acting upon it, but might not accelerate True or False?

Physics
1 answer:
vivado [14]3 years ago
8 0

Answer:

true

Explanation:

if you apply force to the top of a square it will not move

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A boy starts from point A and walks 3 meters toward the north, then turns around and walks 6 meters toward the south.
docker41 [41]

Answer:

Total distance traveled = 9 m

Explanation:

Given:

Distance travel towards north = 3 meter

Distance travel towards south = 6 meter

Find:

Total distance traveled

Computation:

Total distance traveled = Sum of total distance

Total distance traveled = Distance travel towards north + Distance travel towards south

Total distance traveled = 3 m + 6 m

Total distance traveled = 9 m

3 0
3 years ago
Six friends are at a pizzeria. They want to order enough pizza so that each person can eat at least 2/5 . ​ start fraction, 2, d
Lyrx [107]

Friend #1 gets at least 2/5 of a pizza.

Friend #2 gets at least 2/5 .

Friend #3 gets at least 2/5 .

Friend #4 gets at least 2/5 .

Friend #5 gets at least 2/5 .

Friend #6 gets at least 2/5 .

Sum . . . . . . . . . at least  12/5 of a pizza.

Simplify . . . . . . at least  2.4 pizzas.

-- If pizzas can be bought by the half, they should order at least <em>2-1/2 pizzas.</em>

-- If only whole pizzas have to be ordered, then they should order at least <em>3 pizzas.</em>

4 0
4 years ago
99 POINTS!!!!
Papessa [141]
The situation given above can be answered through the concept of the First Law of thermodynamics which states that the change in internal energy is equal to the difference between the work done and the heat added to the system. The work done by the object is negative and the heat added is positive.
             change in internal energy = -500J + 1400 J = 900 J

3 0
3 years ago
Cuales son los factores para que un sobre conductor se genere y aumente la energía termíca
riadik2000 [5.3K]

daisuki

anneyong

mahal kita

te amo

7 0
3 years ago
c. A car was running with a velocity of 20m/s. what will be its velocity after 30s if it's acceleration is 5m/s2​
weqwewe [10]

\large \mathfrak{Solution : }

let's use first equation of motion to solve this ;

  • \boxed{ \boxed{ v = u + at}}

  • v = 20 + (5 \times 30)

  • v = 20 + 150

  • v = 170 \:  \: m/s

Velocity after 30 seconds = 170 m/s

4 0
3 years ago
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