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Nitella [24]
3 years ago
7

An object can have forces acting upon it, but might not accelerate True or False?

Physics
1 answer:
vivado [14]3 years ago
8 0

Answer:

true

Explanation:

if you apply force to the top of a square it will not move

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A girl running around a circular track of radius 200 m completes one
kondor19780726 [428]

Answer:

v = 2 m/s

Explanation:

First, we find the angular velocity of the girl by using the following formula:

Angular\ Velocity =\omega= \frac{Angular\ Distance\ Covered}{Time\ Taken}\\\\\omega = \frac{1\ revolution}{10\ min}\frac{1\ min}{60\ s}\frac{2\pi\ rad}{1\ revolution}\\\\\omega = 0.01\ rad/s

Now, for the average velocity of the girl we can use the following formula:

Average\ Velocity = V = r\omega\\V = (200\ m)(0.01\ rad/s)\\

where,

r = radius = 200 m

therefore,

<u>v = 2 m/s</u>

4 0
3 years ago
How does social theory learning impact on children​
Allushta [10]

Explanation:

Social learning is a hypothesis of learning cycle and social conduct which suggests that new practices can be procured by noticing and copying others. This impacts children because they do things they do not want to.

5 0
3 years ago
A 0.954-kg toy car is powered by three D cells (4.50 V total) connected directly to a small DC motor. The car has an effective e
Natasha2012 [34]

Answer:

0.06 A

Explanation:

We have given mass =0.954 kg

velocity =1.27 m/sec

efficiency =0.361 the output kinetic energy of the motor KE=\frac{1}{2}mv^2=\frac{1}{2}\times 0.954\times 1.27^2=0.769\ J

Efficiency =0.361

so input to the motor = output/efficiency

so input to the motor = \frac{0.769}{0.361}=2.1301

we know that P=\frac{E}{T} where E is energy and T is time so P=\frac{2.1301}{7.88}=0.2703W

We know that power P=VI we have given V=4.5 VOLT

So current I=\frac{P}{V}=\frac{0.2703}{4.5}=0.06 A

3 0
3 years ago
Read 2 more answers
In an "atom smasher," two particles collide head on at relativistic speeds. If the velocity of the first particle is 0.741c to t
USPshnik [31]

Answer:

W_x = 0.9156\ c

Explanation:

given,

velocity of particle 1 = 0.741 c to left

velocity of second particle = 0.543 c to right

relative velocity between the particle = ?

for the relative velocity calculation we have formula

W_x = \dfrac{|u_x - v_x|}{1-\dfrac{u_xv_x}{c^2}}

u_x = 0.543 c

v_x = - 0.741 c

W_x = \dfrac{0.543 c - (-0.741 c)}{1-\dfrac{(0.543 c)(-0.741 c)}{c^2}}

W_x = \dfrac{0.543 c +0.741 c)}{1+\dfrac{(0.543)(0.741)c^2}{c^2}}

W_x = \dfrac{1.284c}{1+0.402363}

W_x = 0.9156\ c

Relative velocity of the particle is W_x = 0.9156\ c

5 0
3 years ago
What is the frequency of a wave having a period equal to 18 seconds? a. 6.6 × 10-2 hertz b. 5.5 × 10-2 hertz c. 3.3 × 10-2 hertz
irakobra [83]
Frequency = 1/period. ... 1 / 18 sec = (1/18) per sec. That's 0.056 per sec or 0.056 Hz. (rounded) (5.6 x 10^-2 Hz)
6 0
3 years ago
Read 2 more answers
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