Exactly the same way that you can photograph a mountain or a skyscraper
with the itty bitty camera in your smartphone.

Lenses are used to form a tiny image of a gigantic object.

7 0

3 years ago

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On an icy road, a 1100 kg car moving at 55 km/h strikes a 480 kg truck moving in the same direction at 37 km/h . The pair is soo

statuscvo [17]

Answer:

Speed of the wreckage = 49.29 km/hr

Explanation:

This question is solved simply by using the conservation of momentum law.

The momentum of the three moving bodies are calculated below:

Momentum of Car 1 : 1100 * 55 = 60500 kg.km/hr

Momentum of Truck : 480 * 37 = 17760 kg.km/hr

Momentum of Car 2 : 1300 * 49 = 63700 kg.km/hr

Total mass of all three vehicles: 1100 + 480 + 1300 = 2880 kg

The final momentum equals the initial momentum if it is conserved. Thus we have the following equation:

Final Momentum = Initial Momentum

Final Velocity * Total mass = Momentum of all three vehicles combined

Final Velocity * 2880 = 60500 + 17760 + 63700

Final Velocity = 49.29 km/hr

7 0

4 years ago

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Due to an influx of wild animals, you need to enclose your garden. You have 500 feet of fencing and will enclose the garden on t

elena55 [62]

Answer:

so length of the fence is 250 feet

Explanation:

Given data

fencing (L) = 500 feet

enclose the garden = 3 sides

to find out

length of the fence

solution

we consider barn length x and width y

so we say x +2y = 500 ........1

we want to maximize length i.e xy = f

so we say

df/dx = ƛ × dL/dx

y = ƛ × 1

and

df/dy = ƛ × df/dy

x = ƛ × 2

from equation 1 we can say

2 ƛ + 2 ƛ = 500

so ƛ = 500/4 = 125

so that x = 2× 125 , y = 125

so x = 250 , y = 125

so length of the fence is 250 feet

3 0

4 years ago

Attached here is the question:

ICE Princess25 [194]

Answer:

t = 6 [s]

Explanation:

In order to solve this problem we must first use this equation of kinematics.

$v_{f}^{2}=v_{o}^{2} +2*a*x$

where:

Vf = final velocity = 0 (the car comes to rest)

Vo = initial velocity = 72 [km/h]

a = acceleration [m/s²]

x = distance = 60 [m]

First we must convert the velocity from kilometers per hour to meters per second.

$72 [\frac{km}{h}]*\frac{1000m}{1km} *\frac{1h}{3600s} =20 [m/s]$

$0=(20)^{2} -2*a*60\\400 = 120*a\\a=3.33[m/s^{2} ]$

Now using this other equation of kinematics.

$v_{f}=v_{o}-a*t$

0 = 20-3.33*t

t = 6[s]

5 0

4 years ago