1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
defon
3 years ago
10

The stopping distance d of a car after the brakes are applied varies directly as the square of the speed r. If a car travelling

70 mph can stop in 270 ft, how many feet will it take the same car to stop whenit is travelling 60 mph?
Physics
1 answer:
Crank3 years ago
4 0
270/70^2  = x/80^2

Cross multiply

270 (6400) = 4900x   

x = 270(6400)/4900

352 and 32/49 feet

Hope this helps


You might be interested in
Which of the following describes a heat sink?
Zielflug [23.3K]

Answer:

B. A device that absorbs and draws heat from a hot object,

dispersing it into the surroundings

Explanation

a heat sink is an object that disperses heat from another object. They're most commonly used in computers, but are also found in cell phones , DVD players and even refrigerators. In computers, a heat sink is an attachment for a chip that prevents the chip from overheating and, in modern computers, it's as important as any other component.

3 0
2 years ago
An airplane capable of an airspeed of 100 km/hr is 60 km off the coast above the sea. If the wind is blowing from the coast out
Nady [450]

To solve this problem we will apply the concepts related to relative speed. We will obtain it from the deduction made on the aircraft as a speed of the two components that act on it. Through the kinematic equations of motion, we can then calculate the time required.

The airspeed of airplane is 100km/h  while the wind is blowing from the coast out to sea at 40km/h. Wind is blowing from the coast out to sea means that it opposes the airspeed. Therefore, resultant relative speed of airplane is

v_r = 100-40=60km/h

Total distance is 60km then with this net velocity we have that the required time is

v = \frac{x}{t} \rightarrow t = \frac{x}{v}

Where,

x = Displacement

t = Time

v = Velocity

Replacing,

t = \frac{60km}{60km/h} = 1hour

t = 60 minutes

Therefore the time taken by the plane to reach the shore is 60 minutes

6 0
3 years ago
Explain why wedges and screws are actually types of inclined planes.
slava [35]
<span>The screw is really just an inclined plane covered around with a tiny pole. The wedge is definitely an inclined plane, since it starts with a point, then rises getting thicker, as an inclined plane. </span>
5 0
3 years ago
Read 2 more answers
Converting 15 miles to kilometer
Dmitry [639]
15 miles to kilometers would be: 24.14 kilometers
8 0
3 years ago
Read 2 more answers
How many stars are there in an Open Cluster?*
Step2247 [10]

Answer:

Very few

Most open clusters form with at least 100 stars

Brainly, please.

4 0
3 years ago
Other questions:
  • A wave of amplitude 0.4 m interferes with a second wave of amplitude 0.23 m traveling in the same direction. What is the largest
    14·1 answer
  • Which describes why the sun is a renewable resource? The sun creates biomass. The sun is continuously releasing energy. The sun
    7·1 answer
  • Three resistors connected in parallel have individual values of 4.0, 6.0, and 10.0 Ω, respectively. If this combination is conne
    13·1 answer
  • How are scientists able to measure the age of earth?
    9·1 answer
  • A copper wire of length 4.00 cm and radius 4.00 mm has a potential difference of 4.00 nV across the ends of the wire. Calculate
    10·1 answer
  • What is radiation? What are the different types? ​
    15·2 answers
  • Lighting is to thunder as lunch
    9·2 answers
  • When a perfume bottle is opened, some liquid changes to gas and the fragrances spreads around the room.
    8·1 answer
  • Please only answer if you are positive. Thanks! Brainliest if correct!
    5·2 answers
  • Calculate the velocity of an object.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!