Sc (21) , Y (39) , La (57) , Ce (58) , Pr (59) , Nd (60) , Pm (61) , Sm (62) , Eu (63) , Gd (64) , Tb (65) , etc (hoped that helped)
<h2>Equation of state of an ideal gas</h2>
<em>The </em><em>ideal gas law is derived</em><em> from the ga</em><em>s laws of Boyle, Charles, Gay Lussac and General.</em>
To solve this exercise, we obtain the data of the exercise:
- V₁ = 52 Lt
- P₁ = 1,2 atm
- P₂ = 0.75 atm
- V₂ = ¿?
<em>The general formula of the </em><em>Equations of state of an ideal gas is:</em>
<h3>P₁V₁=P₂V₂, Where</h3>
- P₁ = Initial pressure
- V₁ = Initial volume
- P₂ = End Pressure
- V₂ = Final Volume
We clear the formula, since it is the value that we must calculate.
<h3>
V₂ = P₁V₁ / P₂</h3>
To solve, we substitute our data in the formula; and we solve
<h3>
V₂ = (1,2 atm)·(52 Lt) / 0.75 atm</h3><h3>
V₂ = 0.832 Lt</h3>
Answer:<em> The </em><em>volume that the gas will occupy</em><em> if the pressure increases to 0.75 atm is </em><em>0.832 lt.</em>
<h2>
See more about this at:</h2><h3>
brainly.com/question/15907283</h3>
Answer:
0.056 miles away
Explanation:
From sound wave,
v = 2x/t .................................. Equation 1
Where v = velocity of sound in air, x = distance of echo, t = time.
making x the subject of the equation,
x = 2v/t........................... Equation 2.
Given: v = 344 m/s, t = 7.6 s.
Substituting into equation 2
x = 2(344)/7.6
x = 90.53 m.
x = 90.53/1609.344
x = 0.056 mile.
Thus the lighting strike 0.056 miles away
Answer:
2.1844 m/s
Explanation:
The principle of conservation of momentum can be applied here.
when two objects interact, the total momentum remains the same provided no external forces are acting.
Consider the whole system , gun and bullet. as an isolated system, so the net momentum is constant. In particular before firing the gun, the net momentum is zero. The conservation of momentum,
assume the bullet goes to right side and the gravitational acceleration =10 
so now the weight of the rifle=
this is a negative velocity to the right side. that means the rifle recoils to the left side
The description of the problem is a bit ambiguous as "<span>increasing at the rate of </span>3 inches more than the time" can be interpreted in many ways. Assuming the increase rate is the (3+t) per second and as it expands for 3 seconds, then the diameter of the sphere would be:
d= (3 + t)*t
d= 3t + t^2= 18
r= 1/2 d
r= 1/2*18= 9
volume= 4/3 * pi * r^3
volume= 4/3 * pi * 9^3
volume= 4/3 * pi * 729= 972 pi cubic inches
