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Semenov [28]
3 years ago
6

Sound travels at a speed of about 344 m/s in air. You see a distant flash of lighting and hear the thunder arrive 7.6 seconds la

ter. How many miles away was the lighting strike? (assume the light takes essentially no time to reach you.)
Express your answer to two significant figures and include the appropriate units.
Physics
1 answer:
Mazyrski [523]3 years ago
8 0

Answer:

0.056 miles away

Explanation:

From sound wave,

v = 2x/t .................................. Equation 1

Where v = velocity of sound in air, x = distance of echo, t = time.

making x the subject of the equation,

x = 2v/t........................... Equation 2.

Given: v = 344 m/s, t = 7.6 s.

Substituting into equation 2

x = 2(344)/7.6

x = 90.53 m.

x = 90.53/1609.344

x = 0.056 mile.

Thus the lighting strike 0.056 miles away

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Answer:

t = 0.196 s

Explanation:

The speed of a pulse is determined by the characteristics of the medium, its density and its resistance to stress, as long as these remain the speed will be constant for which we can use the kinetic expressions of the uniform movement

          v = x / t

          t = x / v

calculate

          t = 2/102

          t = 0.196 s

4 0
3 years ago
Peter designed a road with a curve of radius 30 m that is banked so that a 950 kg car traveling at 40.0 km/h can round it even i
spayn [35]

Answer:

v = 15.56 m/s

v = 56 km/h

Explanation:

When coefficient of friction is approximately zero then we have

F_ncos\theta = mg

F_n sin\theta = \frac{mv^2}{R}

tan\theta = \frac{v^2}{Rg}

here we know that

v = 40 km/h = 11.11 m/s

R = 30 m

tan\theta = \frac{11.11^2}{30\times 9.81}

\theta = 22.75 degree

now when friction coefficient is 0.30 then we have

F_n cos\theta = mg + F_f sin\theta

F_f cos\theta + F_n sin\theta = \frac{mv^2}{R}

now we have

v = \sqrt{Rg(\frac{\mu + tan\theta}{1 - \mu tan\theta})}

v = \sqrt{30(9.81)(\frac{0.30 + tan22.75}{1 - (0.30) tan22.75})}

v = 15.56 m/s

v = 56 km/h

3 0
3 years ago
What is a bond between a positive and a negative ion charge?
klasskru [66]

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Ionic Bond

Explanation:

5 0
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The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: =E−Ryn2 In this equation Ry stands for
skelet666 [1.2K]

Answer:

  λ = 162 10⁻⁷ m

Explanation:

Bohr's model for the hydrogen atom gives energy by the equation

         E_{n} = - k²e² / 2m (1 / n²)

Where k is the Coulomb constant, e and m the charge and mass of the electron respectively and n is an integer

The Planck equation

           E = h f

The speed of light is

          c = λ f

          E = h c /λ

For a transition between two states we have

          E_{n} - E_{m} = - k²e² / 2m (1 / n_{f}² -1 / n_{i}²)

           h c / λ = -k² e² / 2m (1 / n_{f}² - 1/ n_{i}²)

           1 / λ = (- k² e² / 2m h c) (1 / n_{f}² - 1/n_{i}²)

The Rydberg constant with a value of 1,097 107 m-1 is the result of the constant in parentheses

Let's calculate the emission of the transition

            1 /λ = 1.097 10⁷ (1/10² - 1/8²)

            1 / λ = 1.097 10⁷ (0.01 - 0.015625)

            1 /λ = 0.006170625 10⁷

            λ = 162 10⁻⁷ m

3 0
3 years ago
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