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liraira [26]
3 years ago
11

The population of a town is 81,712 and declines continuously at a rate of 4.1% each year. What is the approximate population of

the town in 17 years?
A. 40,699
B. 24,759
C. 164,055
D. 40,105
Mathematics
1 answer:
Ganezh [65]3 years ago
4 0
Data:

P (Final population) = ?
Po (Initial population) = 81712
r (rate) = 4,1% = 0,041
t (time in years) = 17

P = Po - (Po*r*t)
P = 81712 -(81712*0,014*17)
P = 81712 - 56953.264
P =24758.736
\boxed{P \approx 24759}

Answer:
B) 24759

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What is 3 97/100 in simplest form?
chubhunter [2.5K]
Since you want to put this in simplest form ... the easiest way you can do it is


3 (100) + 97

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2 years ago
The fith term of a G.P is 8 times the 2nd term find its common ratio​
Dovator [93]

Answer:

Common ratio r = 2

Step-by-step explanation:

\because the fith term of a G.P is 8 times the 2nd term.

\therefore  \: t_5 = 8\times t_2 \\ \therefore  \: ar^{5-1}=8\times \: ar^{2-1}  \\ \therefore  \: r^{4}=8\times \: r^{1} \\ \therefore  \: r^{3}=8 \\ \therefore  \:r^{3}= {2}^{3}  \\   \hspace{20 pt}\huge \red{ \boxed{\therefore  \:r= {2}}} \\

Hence, common ratio is 2.

6 0
3 years ago
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The reading speed of second grade students in a large city is approximately normal, with a mean of 90 words per
kari74 [83]

Answer:

The probability that a random sample of 10 second grade students from     the city results in a mean  reading rate of more than 96 words per minute

P(x⁻>96) =0.0359

Step-by-step explanation:

<em>Explanation</em>:-

<em>Given sample size 'n' =10</em>

<em>mean of the Population = 90 words per minute</em>

<em>standard deviation of the Population =10 wpm </em>

<em>we will use formula</em>

<em>                            </em>Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }<em></em>

<em>Let X⁻  = 96</em>

                           Z = \frac{96-90 }{\frac{10}{\sqrt{10} } }

                          Z =  1.898

<em>The probability that a random sample of 10 second grade students from     the city results in a mean  reading rate of more than 96 words per minute</em>

<em></em>P(X^{-}>x^{-} ) = P(Z > z^{-} )<em></em>

<em>                    = 1- P( Z ≤z⁻)</em>

<em>                    = 1- P(Z<1.898)</em>

                   = 1-(0.5 +A(1.898)

                   = 0.5 - A(1.898)

                   = 0.5 -0.4641 (From Normal table)

                  = 0.0359

<u><em>Final answer</em></u>:-

The probability that a random sample of 10 second grade students from  

                = 0.0359

4 0
3 years ago
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