1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
barxatty [35]
3 years ago
13

What is the Volume if the Mass = 35g and Density = 5g/cm^3 ?

Mathematics
1 answer:
VLD [36.1K]3 years ago
6 0

density = mass / volume

4 = 35 / v

v = 35/4 = 8.75 cm^3

You might be interested in
A particle is moving along the curve y= 5sqrt(5x+4) . As the particle passes through the point (1,15), its x-coordinate increase
evablogger [386]
The question ask to find the rate of change of the distance from the paticle to the origin at this instant where as a particle is moving along the curve y = 5sqrt(5x+4) and base on my calculation, I came up with an answer of 254/sqrt(226). I hope you are satisfied with my answer and feel free to ask for more 
4 0
3 years ago
Someone please help me!!
mote1985 [20]

Answer:B and E

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
On another map the distance between saugerties and kingston is 2 inches. Whar would tge distance from saugerties to catskill be
Mariana [72]

The question is incomplete. The map is attached as a photo and here is the complete question:

a. What is the actual distance between Saugerties and

Kingston? ___________________________

b. Catskill is 15 miles from Saugerties. What would the

distance on the map be? ___________________________

c. On another map, the distance between Saugerties and

Kingston is 2 inches. What would the distance from Saugerties to

Catskill be on this map? __________________

Since you have asked the answer for part (c) only, here is the answer:

Answer:

<u>The distance from Saugerties to Catskill would be </u><u>3 inches</u><u> on this map.</u>

Step-by-step explanation:

On the given map, the distance between Saugerties and Kingston is 4 inches and the scale is <u>1 inch = 2.5 miles.</u>

To calculate the actual distance in miles between Saugerties and Kingston, consider the given scale:

1 inch ---------- 2.5 miles

4 inches ------ x miles

Cross multiplying:

1x = 2.5 x 4

x = 10 miles

The actual distance between Saugerties and Kingston is 10 miles.

On another map, the distance between Saugerties and Kingston is 2 inches. Which means the scale is 2 inches = 10 miles. So 1 inch = 10/2 = 5 miles

The scale on the other map is 1 inch = 5 miles.

Catskill is 15 miles from Saugerties (given in the previous part). So on the map:

1 inch -------- 5 miles

y inch ------- 15 miles

Cross multiplying:

15 = 5y

y = 15/5

<u>y = 3 inches.</u>

The distance from Saugerties to Catskill would be 3 inches on this map.

7 0
3 years ago
What is the area of this figure? I will give brainliest! :)
jenyasd209 [6]

Answer:

Step-by-step explanation:

Area = (17×35) - (6×15) = 595 - 90 = 505 ft²

3 0
3 years ago
Read 2 more answers
Can someone please help me with this?
ddd [48]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
Other questions:
  • Write and solve a proportion to complete the statement. Round your answer to the nearest hundredth. 90 lb ≈ kg
    5·2 answers
  • John spent about 12.8 hours at a water park. He estimated he spent about 30% of the time waiting in line. What would be a reason
    12·2 answers
  • Solve –4x = –36.<br> –9<br> –32<br> 9<br> –40
    13·2 answers
  • The air around you puts pressure on your body equal to 14.7 pounds per square
    12·1 answer
  • Solve for x. 7(x - 3) = 4(x + 5)
    15·1 answer
  • I really need help with b and c
    10·1 answer
  • Sarah is saving money to buy a microscope. She has saved $25 so far. That's 1/3 of the
    15·1 answer
  • Can someone plz help
    5·1 answer
  • 5 to 7 and please solve with equations thx
    8·2 answers
  • The x-intercepts of cosine become what for the secant function?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!