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Mathematics

2 answers:

amid [387]3 years ago

5 0

for this question, it ask you to draw out.

j + 6 ≥ 7

j ≥ 7 - 6

j ≥ 1

How to draw it:

1. draw a Solid point on the number"1".

2. draw a small vertical line on the top of the point.

3. draw a long horizontal line to number "1" 's right side, and add an arrow in the end of the line.

Nostrana [21]3 years ago

3 0

First bring 6 to the right side by subtracting 6 to both sides (what you do on one side you must do to the other). Since 6 is being added on the left side, subtraction (the opposite of addition) will cancel it out (make it zero) from the left side and bring it over to the right side.

j + 6 ≥ 7

j + 6 - 6 ≥ 7 - 6

j + 0 ≥ 1

j ≥ 1

For the graph will you have a empty or colored in circle?

If the symbol is ≥ or ≤ then the circle will be colored in. This represents that the number the circle is on is included.

If the symbol is > or < then the circle will be empty. This represents that the number the circle is on is NOT included.

Which direction will the ray go?

If the variable is LESS then the number then the arrow will go to the left of the circle.

If the variable is MORE then the number then the arrow will go to the right of the circle.

In this case your inequality is:

j ≥ 1