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Alex_Xolod [135]
3 years ago
10

Tres autos parten de un mismo punto con un intervalo de 1s, con velocidades "3V", "5V" y "Vx", respectivamente hacia un punto "p

", llegando a dicho punto al mismo tiempo los 3 autos. Entonces "Vx" es igual a:
Physics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

Vx = 15V

Explanation:

To find the speed of the third car you take into account that the distance that they travel is the same. Only time is different in one second. Mathematically you have:

x=3vt\ \ \ \ \ (1)\\\\x=5v(t-1)\ \ \ \ (2)\\\\x=v_x(t-2)\ \ \ \ (3)

you equal the first and second equation obtain the time t:

3vt=5v(t-1)\\\\3t=5(t-1)\\\\3t=5t-5\\\\t=\frac{5}{2}s=2.5s

then, you can equal the third and first equation:

3vt=v_x(t-2)\\\\3(2.5s)v=(2.5s-2s)v_x\\\\7.5v=0.5v_x\\\\v_x=15v

hence, Vx = 15V

- - - - - - - - - - - - - - - - - - -

TRANSLATION:

Para encontrar la velocidad del tercer automóvil, tenga en cuenta que la distancia que recorren es la misma. Solo el tiempo es diferente en un segundo. Matemáticamente tienes:

iguala la primera y segunda ecuación obtiene el tiempo t:

entonces, puedes igualar la tercera y primera ecuación:

por lo tanto, Vx = 15V

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Jeff's body contains about 5.46 L of blood that has a density of 1060 kg/m3. Approximately 45.0% (by mass) of the blood is cells
barxatty [35]

Answer:

a

The mass of blood is m= 5.7876kg

b

The number of blood cells is  N_t=1.04*10^{13}

Explanation:

From the question we are told that

         The volume of blood  is  V_b = 5.46 \ L = \frac{5.46}{1000} = 0.00546m^3

         The density of the blood is  \rho_b = 1060 kg/m^3

         % of blood  that is  cell is  = 45.0%

        % of the blood that is  plasma is  = 55.0%

        density of blood cell is  \rho_d = 1125kg/m^3

        % of cell that are white is  = 1%

        % of cell that is red is  = 99%

        The diameter of the red blood cell is  = 7.5 \mu m = 7.5*10^{-6}m

         The radius of the red blood cell is  = \frac{7.5*10^{-6}}{2} = 3.75*10^{-6}m

Generally the mass is mathematically  represented as

               m = \rho_b * V_b

Substituting value

            m = 1060 * 0.00546

               m= 5.7876kg

Mass of cell is m_c = 45% of m

                         = 0.45 * 5,7876

                         = 2.60442 kg

The volume of cells is V_c = \frac{m_c}{\rho_d}

                                      = \frac{2.60442}{1125}

                                      = 2.315 *10^{-3} m^3

The volume of white blood cell is V_w = 1% of volume of cells

                                                         = \frac{1}{100} * 2.315*10^{-3}

                                                       = 2.315*10^{-5}m^3

The volume of a single cell is V_s = 4 \pi r^3

                                                                        = 4*(3.142) * (3.75*10^{-6})^3

                                                                        = 2.21*10^{-16}m^3

The volume of red blood cells is V_r = V_c - V_w

                                                           =2.315*10^{-3} - 2.315*10^{-5}

                                                           = 2.29*10^{-3}m^3

The number of red blood cell is  = \frac{V_r}{V_s}

                                                     = \frac{2.29 *10^{-3}}{2.21*10^{-16}}

                                                    = 1.037*10^{13}

The Number of white blood cell is   =\frac{V_w}{V_s}

                                                          = \frac{2.315 * 10^{-5}}{2.21*10^{-16}}

                                                          = 1.04*10^{11}

The total number of blood cells is  N_t= 1.037*10^{13} + 1.04*10^{11}

                                                        N_t=1.04*10^{13}

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