Tres autos parten de un mismo punto con un intervalo de 1s, con velocidades "3V", "5V" y "Vx", respectivamente hacia un punto "p
1 answer:
Answer:
Vx = 15V
Explanation:
To find the speed of the third car you take into account that the distance that they travel is the same. Only time is different in one second. Mathematically you have:
you equal the first and second equation obtain the time t:
then, you can equal the third and first equation:
hence, Vx = 15V
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TRANSLATION:
Para encontrar la velocidad del tercer automóvil, tenga en cuenta que la distancia que recorren es la misma. Solo el tiempo es diferente en un segundo. Matemáticamente tienes:
iguala la primera y segunda ecuación obtiene el tiempo t:
entonces, puedes igualar la tercera y primera ecuación:
por lo tanto, Vx = 15V
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Forward thrust has positive values and reverse thrust has negative values.
Thrust is a sudden push or pull in a certain direction.
a)
Flight speed u = 150 km/h
1 km/h = km/s
therefore, 150 km/h = 41.67 km / s
The thrust force represents the horizontal or x-component of momentum equation:
T = 50 * (150 - 41.67)
T = 5416.67 N
Therefore, the value of forward thrust is 5416.67 N.
b)
Now the exhaust velocity is now vertical due to reverse thrust application, then it has a zero horizontal component,
thus thrust equation is:
T = 50 * (0 - 41.67)
T = -2083.5 N
Therefore, the thrust force T is -2083.5 N in the reverse direction.
c)
Now the exhaust velocity and flight velocity is zero, then it has a zero horizontal component, thus thrust is also zero because
T = 0
Therefore, there is no difference in two velocities in x direction.
The given question is incomplete, the complete question is,
"The idling engines of a landing turbojet produce forward thrust when operating in a normal manner, but they can produce reverse thrust if the jet is properly deflected. Suppose that while the aircraft rolls down the runway at 150 km/h the idling engine consumes air at 50 kg/s and produces an exhaust velocity of 150 m/s.
a. What is the forward thrust of this engine?
b. What are the magnitude and direction (i.e., forward or reverse) if the exhaust is deflected 90 degree without affecting the mass flow?
c. What are the magnitude and direction of the thrust (forward or reverse) after the plane has come to a stop, with 90 degree exhaust deflection and an airflow of 40 kg/s?"
To know more about thrust,
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Answer:
Explanation:
Let's start with the definition of a constant velocity.
If the velocity magnitude, in three dimensions, is a constant value (C) we have a constant velocity, which means.
Now, we know that the dot product between v(t) and v(t) is the |v|².
If we take the derivative whit respect to time in both sides of this equation we will have:
We apply the product rule on the left side and the right side will zero because the derivative of a constant is 0.
We know that dv(t)/dt = a(t) (using the acceleration definiton)
Therefore, we conclude:
If the dot product is 0, it means that v(t) and a(t) are orthogonal.
I hope it helps you!