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Alex_Xolod [135]
3 years ago
10

Tres autos parten de un mismo punto con un intervalo de 1s, con velocidades "3V", "5V" y "Vx", respectivamente hacia un punto "p

", llegando a dicho punto al mismo tiempo los 3 autos. Entonces "Vx" es igual a:
Physics
1 answer:
kkurt [141]3 years ago
7 0

Answer:

Vx = 15V

Explanation:

To find the speed of the third car you take into account that the distance that they travel is the same. Only time is different in one second. Mathematically you have:

x=3vt\ \ \ \ \ (1)\\\\x=5v(t-1)\ \ \ \ (2)\\\\x=v_x(t-2)\ \ \ \ (3)

you equal the first and second equation obtain the time t:

3vt=5v(t-1)\\\\3t=5(t-1)\\\\3t=5t-5\\\\t=\frac{5}{2}s=2.5s

then, you can equal the third and first equation:

3vt=v_x(t-2)\\\\3(2.5s)v=(2.5s-2s)v_x\\\\7.5v=0.5v_x\\\\v_x=15v

hence, Vx = 15V

- - - - - - - - - - - - - - - - - - -

TRANSLATION:

Para encontrar la velocidad del tercer automóvil, tenga en cuenta que la distancia que recorren es la misma. Solo el tiempo es diferente en un segundo. Matemáticamente tienes:

iguala la primera y segunda ecuación obtiene el tiempo t:

entonces, puedes igualar la tercera y primera ecuación:

por lo tanto, Vx = 15V

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Answer:

T’= 4/3 T  

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Explanation:

For this problem let's use Newton's second law applied to each body

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Axis y

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Body B

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We write the equations

    T = m_A a

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We solve this system of equations

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    a = m_B / (m_A + m_B) g

In this initial case

     m_A = M

     m_B = M

     a = M / (1 + 1) M g

     a = ½ g

Let's find the tension

    T = m_A a

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    T = ½ M g

Now we change the mass of the second block

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   T’/ T = 4/3

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The new tension is 4/3 = 1.33 of the previous tension the answer  e

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Now, We need to calculate the volume of large cube

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