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erastova [34]
3 years ago
5

A cube of osmium metal 1.500 cm on a side has a mass of 76.31 g at 25 ?c. part a what is its density in g/cm3 at this temperatur

e?
Physics
1 answer:
gayaneshka [121]3 years ago
4 0
The volume of the cube osmium metal is calculated by multiplying the given dimension to itself three times. 
                                    v = (1.5 cm)(1.5 cm)(1.5 cm)
                                    v = 3.375 cm³
Density is calculated by dividing the mass by volume.
                                    d = (76.31 g)/(3.375 cm³)
                                     d = 22.61 g/cm³

Thus, the density of the metal is approximately 22.51 g/cm³.
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A 0.5-kg ball moving at 5 m/s strikes a wall and rebounds in the opposite direction with a speed of 2 m/s. If the impulse occurs
mart [117]

<em>Given that:</em>

                       mass of the ball (m) = 0.5 Kg ,

                    ball strikes the wall (v₁) = 5 m/s ,

rebounds in opposite direction (v₂) = 2 m/s,

                                time duration (t) = 0.01 s,

        <em> Determine the force (F) = ?</em>

We know that from Newton's II law,

                                <em>F = m. a</em>  Newtons  

                                  (velocity acting in opposite direction, so <em>a = ( (v₁ + v₂)/t</em>

                                   = m × (v₁ + v₂)/t

                                   = 0.5 × (5 + 2)/0.01

                                  = 350 N

<em>The force acting up on the ball is 350 N</em>

                                     

6 0
3 years ago
A 46.5-kg ball has a momentum of 57.2 kg m/s. What is the ball's speed?
Serhud [2]

Answer:

1.23 m/s

Explanation:

p=mv

57.2 = 46.5v

v= 57.2/46.5

v= 1.23

If you want to verify your answer, just insert the value of v in the equation.

5 0
2 years ago
An hydrogen molecule consists of two hydrogen atoms whose total mass is 3.3×10−27 kg and whose moment of inertia about an axis p
dlinn [17]

Answer:

6.9631\times 10^{-11}\ m

Explanation:

I = Moment of inertia = 4\times 10^{-48}\ kg m^2

m = Mass of two atoms = 2m = 3.3\times 10^{-27}\ kg

r  = distance between axis and rotation mass

Moment of inertia of the system is given by

I=mr^2\\\Rightarrow I=2mr^2\\\Rightarrow 4\times 10^{-48}=3.3\times 10^{-27}\times r^2\\\Rightarrow r=\sqrt{\frac{4\times 10^{-48}}{3.3\times 10^{-27}}}\\\Rightarrow r=3.48155\times 10^{-11}\ m

The distance between the atoms will be two times the distance between axis and rotation mass.

d=2r\\\Rightarrow d=2\times 3.48155\times 10^{-11}\\\Rightarrow d=6.9631\times 10^{-11}\ m

Therefore, the distance between the two atoms is 6.9631\times 10^{-11}\ m

3 0
3 years ago
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