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Sever21 [200]
3 years ago
12

. Two buses depart from Chicago, one going to New York and one to San Francisco. Each bus travels at a speed of 30 m/s. Do they

have equal velocities? Explain.
Physics
1 answer:
zaharov [31]3 years ago
3 0

Answer:

They don't have equal velocities

Explanation:

We have one bus travelling from Chicago to New York at 30 m/s and one bus travelling from Chicago to San Francisco at 30 m/s.

This is a cheat question. You need to remember that velocity  is a vector. Remember that a vector has a direction and a module. So, the answer will be true, if both buses meet both conditions (direction and module). Let's start to analyze:

Module: In this case is 30 m/s for both buses

Direction: In this case is where the buses are heading. One is going to New York, and one is going to San Francisco. So the directions are different.

As module and direction are not the same for both buses we can say that they don't have equal velocities.

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A sled slides along a horizontal surface on which the coefficient of kinetic friction is 0.25. Its velocity at point A is 8.6 m/
jenyasd209 [6]

Answer:

\Delta t =1.31\ s

Explanation:

given,

coefficient of kinetic friction, μ = 0.25

Speed of sled at point A = 8.6 m/s

Speed of sled at point B = 5.4 m/s

time taken to travel from point A to B.

we know,

J = F Δ t

J is the impulse

where  F is the frictional force.

t is the time.

we also know that impulse is equal to change in momentum.

J = m(v_f - v_i)

frictional force

F = μ N

where as N is the normal force

now,

F\Delta t = m(v_f -v_i)

\mu m g \times \Delta t = m(v_f-v_i)

\mu g \times \Delta t = v_f-v_i

\Delta t =\dfrac{v_f-v_i}{\mu g}

\Delta t =\dfrac{8.6-5.4}{0.25\times 9.8}

\Delta t =1.31\ s

time taken to move from A to B is equal to 1.31 s

3 0
3 years ago
Read 2 more answers
Two gliders collide on an air track moving in from opposite directions, and they bounce back. The masses of the gliders are 0.20
timurjin [86]

Answer:

so initial momentum is 0.22kgm/s

Explanation:

m1=0.20kg

m2=0.30kg

initial velocity of m1=u1=0.50m/s

initial velocity of m2=u2=0.40m/s

total momentum of the system before collision

Pi=m1u1+m2u2

Pi=0.20kg×0.50m/s+0.30kg×0.40m/s

Pi=0.1kgm/s+0.12kgm/s

Pi=0.22kgm/s

3 0
3 years ago
D
GenaCL600 [577]

Answer:

I don't know about these problems

Explanation:

I don't know about these problems at all.

7 0
3 years ago
Good afternoon.....from bangladesh....
Step2247 [10]

Answer:

good afternoon

Explanation:

4 0
3 years ago
Read 2 more answers
A damped LC circuit consists of a 0.17 μF capacitor and a 15 mH inductor with resistance 1.4Ω. How many cycles will the circuit
Dafna1 [17]

Answer:

number of cycles = 4.68 × 10⁴ cycles

Explanation:

     In damped RLC oscillation

voltage (V(t)) = V_o\ e^{-\dfrac{tR}{2L}}............(1)

given,

C = 0.17μF = 0.17 × 10⁻⁶ F

R = 1.4 Ω

L = 15 m H = 15 × 10⁻³ H              V(t) = V₀/2

From the equation (1)

\dfrac{V_0}{2} = V_0\ e^{-\dfrac{tR}{2L}}

 2 = e^{\dfrac{tR}{2L}}

taking log both side

ln ( 2 ) = \dfrac{tR}{2L}

t = \dfrac{2 L ln(2)}{R}

t = \dfrac{2 \times 15 ln(2)}{1.4}

t = 14.85 sec

time period

T= 2\pi \sqrt{LC}

T= 2\pi \sqrt{0.015 \times 0.17 \times 10^{-6}}

T = 3.172 × 10⁻⁴

number of cycle =\dfrac{t}{T}

                           =  \dfrac{14.85}{3.172 \times 10^{-4}}

  number of cycles = 4.68 × 10⁴ cycles

8 0
3 years ago
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