Answer:

Explanation:
given,
coefficient of kinetic friction, μ = 0.25
Speed of sled at point A = 8.6 m/s
Speed of sled at point B = 5.4 m/s
time taken to travel from point A to B.
we know,
J = F Δ t
J is the impulse
where F is the frictional force.
t is the time.
we also know that impulse is equal to change in momentum.

frictional force
F = μ N
where as N is the normal force
now,






time taken to move from A to B is equal to 1.31 s
Answer:
so initial momentum is 0.22kgm/s
Explanation:
m1=0.20kg
m2=0.30kg
initial velocity of m1=u1=0.50m/s
initial velocity of m2=u2=0.40m/s
total momentum of the system before collision
Pi=m1u1+m2u2
Pi=0.20kg×0.50m/s+0.30kg×0.40m/s
Pi=0.1kgm/s+0.12kgm/s
Pi=0.22kgm/s
Answer:
I don't know about these problems
Explanation:
I don't know about these problems at all.
Answer:
number of cycles = 4.68 × 10⁴ cycles
Explanation:
In damped RLC oscillation
voltage (V(t)) = V_o\ e^{-\dfrac{tR}{2L}}............(1)
given,
C = 0.17μF = 0.17 × 10⁻⁶ F
R = 1.4 Ω
L = 15 m H = 15 × 10⁻³ H V(t) = V₀/2
From the equation (1)


taking log both side



t = 14.85 sec
time period


T = 3.172 × 10⁻⁴
number of cycle =
= 
number of cycles = 4.68 × 10⁴ cycles