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Sever21 [200]
4 years ago
12

. Two buses depart from Chicago, one going to New York and one to San Francisco. Each bus travels at a speed of 30 m/s. Do they

have equal velocities? Explain.
Physics
1 answer:
zaharov [31]4 years ago
3 0

Answer:

They don't have equal velocities

Explanation:

We have one bus travelling from Chicago to New York at 30 m/s and one bus travelling from Chicago to San Francisco at 30 m/s.

This is a cheat question. You need to remember that velocity  is a vector. Remember that a vector has a direction and a module. So, the answer will be true, if both buses meet both conditions (direction and module). Let's start to analyze:

Module: In this case is 30 m/s for both buses

Direction: In this case is where the buses are heading. One is going to New York, and one is going to San Francisco. So the directions are different.

As module and direction are not the same for both buses we can say that they don't have equal velocities.

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a 20 kg projectile is launched from a cannon. a. if the projectile leaves the cannon with a velocity of 54 m/s, what is the work
Artyom0805 [142]

Answer:

KE = 1/2 M v^2       kinetic energy of projectile

KE = 1/2 * 20 * (54 m/s)^2 = work done on projectile

W = 10 * 54^2 = work done on projectile

W = 29,160 J

7 0
2 years ago
Three liquids are at temperatures of 6 ◦C, 23◦C, and 38◦C, respectively. Equal masses of the first two liquids are mixed, and th
kupik [55]

The equilibrium temperature is T13=3.12 ◦C

<u>Explanation:</u>

<u>Given </u>

The temperature of liquids: T1=6◦C, T2=23◦C, T3=38◦C

The temperature of 1+2 liquids mix: T12= 13◦C.

The temperature of 2+3 liquids mix: T23=26.8 ◦C.

The temperature of 1+3 liquids mix: T13= ??

<u>1.When the first two liquids are mixed:</u>

  • mC1(T1-T12)+mC2(T2-T12)=0
  • C1(6-13)=C2(23-13)=0
  • 7C1=10C2
  • C1=1.42C2

<u>2.When the second and third liquids are mixed</u><u>:</u>

  • mC2(T2-T23)+mC3(T3-T23)=0
  • C2(23-26.8)=C3(38-26.8)=0
  • 3.8C2=12.8C3
  • C2=3.36C3

<u>3.When the first and third liquids are mixed:</u>

  • mC1(T1-T13)+mC3(T3-T13)=0
  • C1(6-T13)+C3(38-T13)=0
  • C1=1.42C2  C2=3.36C3
  • C1=1.42C2(3.36C3)
  • C1=4.77C3
  • C1(6-T13)+C3(38-T13)=0
  • 4.77C3(6-T13)+C3(38-T13)=0
  • By solving the equation we get,
  • T13=3.12 ◦C
  • The equilibrium temperature is T13=3.12 ◦C

<u></u>

7 0
3 years ago
Which of the following explains why parallax is used to measure stars?
enyata [817]

D, it provides greater accuracy for measuring stars far from the earth.

7 0
3 years ago
Read 2 more answers
The battery of a flashlight develops 3 V, and the current through the bulb is 200 mA.What power is absorbed by the bulb?
Verizon [17]

Answer : The power absorbed by the bulb is, 0.600 W

Explanation :

As we know that,

Power = Voltage × Current

Given:

Voltage = 3 V

Current = 200 mA = 0.200 A

Conversion used : (1 mA = 0.001 A)

Now put all the given values in the above formula, we get:

Power = Voltage × Current

Power = 3V × 0.200 A

Power = 0.600 W

Thus, the power absorbed by the bulb is, 0.600 W

3 0
4 years ago
The 5-lb collar is released from rest at A and travels along the frictionless guide. Determine the speed of the collar when it s
Sholpan [36]

Answer:

Explanation:

Stiffness of spring k equal to 4 lb/ft.

Unstretched length of the spring L is equal to 0.5 feet.  

Weight of the collar W is 15lb

Radius of curvature of curve guide is 1 feet

length of vertical rod is 1.5 feet

Initial speed of collar when released from rest at A is 0 feet per seconds  

use the energy conservation equation

 P_A +K_A=P_B+K_B

Estimate the potential energy , component as position B as below

P_A=Wh_1+\frac{1}{2} ks^2_1\\\\=5\times(1.5+1)+\frac{1}{2} \times 4 \times(1.5+1-0.5)^2\\\\=20.5lb.ft

Estimate the kinetic energy , component as position A as below

K_A=\frac{1}{2} \frac{W}{g} V^2_1\\\\=\frac{1}{2} \frac{5}{32.2} \times0^2\\\\=0lb.ft

Estimate the kinetic energy , component as position B as below

K_A=\frac{1}{2} \frac{W}{g} V^2_2\\\\=\frac{1}{2} \frac{5}{32.2} \times V^2_2\\\\=00777V^2_2

Substitute 20.5lb- ft for P_A

0.5lb-ft for P_B

0lb -ft for K_A

0.0777V_2^2 for K_B

20.5+0=0.5+0.777V^2_2\\\\V^2_2=257.6\\\\V_2=16.05

= 16.05ft/sec

7 0
3 years ago
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