Answer:
KE = 1/2 M v^2 kinetic energy of projectile
KE = 1/2 * 20 * (54 m/s)^2 = work done on projectile
W = 10 * 54^2 = work done on projectile
W = 29,160 J
The equilibrium temperature is T13=3.12 ◦C
<u>Explanation:</u>
<u>Given </u>
The temperature of liquids: T1=6◦C, T2=23◦C, T3=38◦C
The temperature of 1+2 liquids mix: T12= 13◦C.
The temperature of 2+3 liquids mix: T23=26.8 ◦C.
The temperature of 1+3 liquids mix: T13= ??
<u>1.When the first two liquids are mixed:</u>
- mC1(T1-T12)+mC2(T2-T12)=0
- C1(6-13)=C2(23-13)=0
- 7C1=10C2
- C1=1.42C2
<u>2.When the second and third liquids are mixed</u><u>:</u>
- mC2(T2-T23)+mC3(T3-T23)=0
- C2(23-26.8)=C3(38-26.8)=0
- 3.8C2=12.8C3
- C2=3.36C3
<u>3.When the first and third liquids are mixed:</u>
- mC1(T1-T13)+mC3(T3-T13)=0
- C1(6-T13)+C3(38-T13)=0
- C1=1.42C2 C2=3.36C3
- C1=1.42C2(3.36C3)
- C1=4.77C3
- C1(6-T13)+C3(38-T13)=0
- 4.77C3(6-T13)+C3(38-T13)=0
- By solving the equation we get,
- T13=3.12 ◦C
- The equilibrium temperature is T13=3.12 ◦C
<u></u>
D, it provides greater accuracy for measuring stars far from the earth.
Answer : The power absorbed by the bulb is, 0.600 W
Explanation :
As we know that,
Power = Voltage × Current
Given:
Voltage = 3 V
Current = 200 mA = 0.200 A
Conversion used : (1 mA = 0.001 A)
Now put all the given values in the above formula, we get:
Power = Voltage × Current
Power = 3V × 0.200 A
Power = 0.600 W
Thus, the power absorbed by the bulb is, 0.600 W
Answer:
Explanation:
Stiffness of spring k equal to 4 lb/ft.
Unstretched length of the spring L is equal to 0.5 feet.
Weight of the collar W is 15lb
Radius of curvature of curve guide is 1 feet
length of vertical rod is 1.5 feet
Initial speed of collar when released from rest at A is 0 feet per seconds
use the energy conservation equation

Estimate the potential energy , component as position B as below

Estimate the kinetic energy , component as position A as below

Estimate the kinetic energy , component as position B as below

Substitute 20.5lb- ft for 
0.5lb-ft for 
0lb -ft for 


= 16.05ft/sec