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4 years ago

Which effect is created when two sound waves that are close in pitch

Physics

1 answer:

Temka [501]4 years ago

5 0

Answer:

C. Beats

Explanation:

When waves are interfering with each other, the sound is louder in some places and softer in others. As a result, we hear pulses or beats in the sound.

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A particle moves along a path described by y=Ax^3 and x = Bt, where tt is time. What are the units of A and B?

Sergeu [11.5K]

Answer:

In a nutshell, units of A and B are $\frac{1}{[l]^{2}}$ and $\frac{[l]}{[t]}$ , respectively.

Explanation:

From Dimensional Analysis we understand that $x$ and $y$ have length units ( $[l]$ ) and $t$ have time units ( $[t]$ ). Then, we get that:

$[l] = A\cdot [l]^{3}$ (Eq. 1)

$[l] = B\cdot [t]$ (Eq. 2)

Now we finally clear each constant:

$A = \frac{[l]}{[l]^{3}}$

$A = \frac{1}{[l]^{2}}$

$B = \frac{[l]}{[t]}$

In a nutshell, units of A and B are $\frac{1}{[l]^{2}}$ and $\frac{[l]}{[t]}$ , respectively.

4 0

4 years ago

El extremo de una cuerda se mueve de tal manera que las partículas de la cuerda emplean 0.25 segundos para producir una vibració

insens350 [35]

Responder:

T = 0.25 segundos

f = 4 Hz

Explicación:

Paso uno:

datos dados

se nos dice que las partículas tardan 0,25 segundos en completar una vibración

por lo tanto, el período es de 0,25 segundos

¿Qué es un período de vibración?

Un período T es el tiempo necesario para que un ciclo completo de vibración pase por un punto determinado.

la expresión para el período se da a continuación.

T = 1 / f

¿Cuál es la frecuencia de vibración?

Básicamente, se refiere a la frecuencia con la que ocurren las vibraciones.

la frecuencia es una tasa, se expresa como la inversa del período

f = 1 / T

t = 1 / 0.25

f = 4 Hz

6 0

3 years ago

Một mặt phẳng vô hạn tích điện đều, mật độ σ = 4.10-9 C/cm2, đặt thẳng đứng trong không khí. Một quả cầu nhỏ có khối lượng 8 g,

dusya [7]

Answer:

The angle is 18.3 degree.

Explanation:

A uniformly charged infinite plane, density σ = 4 x 10^-9 C/cm^2, is placed vertically in air. A small ball of mass 8 g, with charge q = 10^-8 C, hangs close to the plane, so that the string is initially parallel to the plane. Take g = 9.8m/s2. When in equilibrium, by what angle is the string hanging the ball to the plane?

surface charge density, σ = 4 x 10^-5 C/m^2

Charge, q = 10^-8 C

mass, m = 0.008 kg

Let the angle is A and the tension in the string is T.

The electric field due to a plane is

$E =\frac{\varepsilon \sigma }{2\varepsilon o}\\\\E =\frac{4\times 10^{-5}}{2\times 8.85\times 10^{-12}}\\\\E = 2.26\times 10^6 V/m \\$

Now equate the forces,

$T sin A = q E.... (1)\\\\T cos A = m g ..... (2)\\\\divide (1) by (2)\\\\tan A = \frac{10^{-8}\times 2.6\times 10^6}{0.008\times 9.8}\\\\tan A = 0.33\\\\ A = 18.3 degree$

5 0

3 years ago

A technician is checking refrigerant system pressures. Both high- and low-side service ports are located on the A/C compressor.

konstantin123 [22]

Answer:

Two major causes are outline bellow

1. The presence of air in the system

2. Clogged condenser

Explanation:

1. The presence of air in the system

One of the causes that have been established in relation to high compressor discharge pressure is the presence of air in the system. When this takes place, your best solution is to recharge the system.

2. Clogged condenser

Another is a clogged condenser in which case you will need to clean the condenser so that it will function properly. When you happen to spot that the discharge valve is closed and it is causing high discharge pressure on the compressor, you can solve that easily by opening the valve

5 0

4 years ago

A hot air balloon rises at a constant speed of 13 meters/second relative to the air. There is a wind blowing eastwards at a spee

Airida [17]

Answer:

13.02 m/s the velocity and 86.92 degrees the direction relative to ground

Explanation:

We need to add velocities in vector addition to find the resultant velocity " $v$ " of the balloon (the 13 m/s and the 0.7 m/s).

The velocities are at 90 degrees from each other (one pointing up and the other to the East). Notice from the attached image that the resultant velocity vector (picture in red) is actually the hypotenuse of a right angle triangle.

So we use Pythagoras to find the length (magnitude) of the resultant velocity vector:

$v = \sqrt{13^2 +0.7^2} = 13.018832...$

we can round the answer to 13.02 m/s

Now we need to find the angle that this new vector makes with the ground by using the definition of tangent of an angle that relates the two quantities that we just added:

$tan (\theta) = 13/0.7 \\ \theta = arctan (\frac{13}{07} = 86.91781918...$

So we round it to 86.92 degrees

5 0

4 years ago